Python循环列出打印索引或数组

Question

下午好， 蟒蛇新手在这里。我正在尝试返回从文本文件中抓取的客户信息列表。我需要输出采用名称、帐号、日期格式。我最初的想法是，

抓取数据 创建列表 按 index_number 打印，例如（姓名 1，帐号 1，日期 1）

很遗憾，这不起作用，因为列表将打印出所有姓名，然后是所有帐号，然后是日期。我需要将列表打印为姓名、帐号、日期。

我很确定这是因为我运行循环的方式。下面是我一直在处理的代码。

   import re

fin = open(destFileLoc,"r")
text = fin.read()


nameMatch = re.findall(r'\n\w+\s+\w+\s\w+', text)
# for i in range(len(nameMatch)):
#     name = nameMatch # print("Name: " + nameMatch[i])

acctMatch = re.findall(r'\s{4}\d{8}', text)
# for i in range(len(acctMatch)):
#     account = acctMatch  ##print("Account Num: " + acctMatch[i])

dateMatch = re.findall(r'(\d+/\d+/\d+)', text)
# for i in range(len(dateMatch)):
#     date = dateMatch  ## print("Date of Service : " + dateMatch[i])

patList = [[nameMatch], [acctMatch], [dateMatch]]
for i in range(patList):
    print("====== Name     Account Number       Date ======\n" + str(nameMatch[i]), str(acctMatch[i]), str(dateMatch[i]))

Answer 1

您可以尝试使用 zip 组合多个列表

for name, acctNum, date in zip(nameMatch, acctMatch, dateMatch):
    print(str(name), str(acctNum), str(date))

Answer 2

试试...

另见The format module

nameMatch =["Smith", "Jones", "Thompson"]
acctMatch =["12345", "54321", "22333"]
dateMatch =["2019-10-1", "2019-10-2", "2019-10-3"]

a = list(zip(
    nameMatch,
    acctMatch, 
    dateMatch
))

print(a)

for _list in a:
    print("=========================")
    print("Printing the list itself: ", _list)
    print ('Printing the items in _list:', _list[0], _list[1], _list[2])

print("=========================")
print ('Printing the items with format and columns:')
for _list in a:
    print( '{0:.<10}{1:.<10}{2:.<10}'.format(_list[0], _list[1], _list[2]))

输出：

[('Smith', '12345', '2019-10-1'), ('Jones', '54321', '2019-10-2'), ('Thompson', '22333', '2019-10-3')]
=========================
Printing the list itself:  ('Smith', '12345', '2019-10-1')
Printing the items in _list: Smith 12345 2019-10-1
=========================
Printing the list itself:  ('Jones', '54321', '2019-10-2')
Printing the items in _list: Jones 54321 2019-10-2
=========================
Printing the list itself:  ('Thompson', '22333', '2019-10-3')
Printing the items in _list: Thompson 22333 2019-10-3
=========================
Printing the items with format and columns:
Smith.....12345.....2019-10-1.
Jones.....54321.....2019-10-2.
Thompson..22333.....2019-10-3.