从文件中删除数组项

Question

假设我们有一个数组项列表

例如：- a,b,c,d

需要从充满数据的文件中删除，我遗漏了一些东西，任何人都可以帮助我实现这一点，在此先感谢

public static void rmvFromXML(String strFilePath,
        String strTmpFilePath) throws IOException {

    String currentLine = "";
    List<String> list = new ArrayList<String>();
    list.add("a");
    list.add("b");
    list.add("c");
    list.add("d");

    BufferedReader reader = new BufferedReader(new FileReader(strFilePath));
    BufferedWriter fileWriter = null;

    fileWriter = new BufferedWriter(new OutputStreamWriter(
            new FileOutputStream(strTmpFilePath)));

    while ((currentLine = reader.readLine()) != null) {

        String trimmedLine = currentLine.trim();
        System.out.println("Trimmed Line    :- " + trimmedLine);

        for (String value : list) {

            System.out.println("Array Value:-   " + value);
            if (trimmedLine.equals(value))

                continue;

            fileWriter.write(trimmedLine + System.getProperty("line.separator"));
        }
    }
    fileWriter.close();
    reader.close();
}

Answer 1

您可以使用正则表达式。这样您就不必迭代并检查 行包含你的字符串

while ((currentLine = reader.readLine()) != null) {
Pattern removeWords = Pattern.compile("\\b(?:a|b|c|d)\\b\\s*", Pattern.CASE_INSENSITIVE);
Matcher fix = removeWords.matcher(currentLine);
String fixedString = fix.replaceAll("");
}

试试上面的方法

input :
abcdefg

output
efg

Answer 2

您需要在文件中的每行中替换提供的子字符串，因此用空格替换它：

public static void rmvFromXML(String strFilePath,
                                  String strTmpFilePath) throws IOException {

        String currentLine = "";
        List<String> list = new ArrayList<>();
        list.add("a");
        list.add("b");
        list.add("c");
        list.add("d");

        BufferedReader reader = new BufferedReader(new FileReader(strFilePath));
        BufferedWriter fileWriter = null;

        fileWriter = new BufferedWriter(new OutputStreamWriter(
                new FileOutputStream(strTmpFilePath)));

        while ((currentLine = reader.readLine()) != null) {

            String trimmedLine = currentLine.trim();
            System.out.println("Trimmed Line    :- " + trimmedLine);

            for (String value : list) {
                System.out.println("Array Value:-   " + value);
                trimmedLine = trimmedLine.replaceAll(value, "");
            }

            fileWriter.write(trimmedLine + System.getProperty("line.separator"));
        }
        fileWriter.close();
        reader.close();
    }

现在输入：

sdfsdf
sdfsdf
sfsdfs
fa
a
 b
c
asdasdad
   d   
asdasd

我们得到输出：

sfsf
sfsf
sfsfs
f



ss

ss

Answer 3

替换：

    for (String value : list) {

        System.out.println("Array Value:-   " + value);
        if (trimmedLine.equals(value))

            continue;

        fileWriter.write(trimmedLine + System.getProperty("line.separator"));
    }

作者：

    bool found=false:
    for (String value : list) {

        System.out.println("Array Value:-   " + value);
        if (trimmedLine.equals(value))

            found=true;
    }
    if(!found)
        fileWriter.write(trimmedLine + System.getProperty("line.separator"));

fileWriter.write 调用应该在“for”循环之外。