试试下面的方法。
private static void insertAfter(long[][] array, int value, long[] insertion) {
boolean found = false;
for (int i = 0; i < array.length; i++) {
long[] sub = array[i];
for (int j = 0; j < sub.length; j++) {
if (sub[j] == value) {
long[] newSub = new long[sub.length + insertion.length];
System.arraycopy(sub, 0, newSub, 0, j + 1);
System.arraycopy(insertion, 0, newSub, j + 1, insertion.length);
System.arraycopy(sub, j + 1, newSub, j + 1 + insertion.length, sub.length - j - 1);
array[i] = newSub;
found = true;
break;
}
}
if (found) break;
}
}
示例用法:
insertAfter(questionOrder, 7, new long[]{12, 13});
System.out.println(gson.toJson(questionOrder));
这将打印[[4,5],[3,1,6,7,12,13],[34,21,55]]
要删除元素,您可以使用类似但稍作修改的逻辑:
private static long[][] remove(long[][] array, int value) {
boolean found = false;
int emptyIndex = -1;
for (int i = 0; i < array.length; i++) {
long[] sub = array[i];
for (int j = 0; j < sub.length; j++) {
if (sub[j] == value) {
long[] newSub = new long[sub.length - 1];
System.arraycopy(sub, 0, newSub, 0, j);
System.arraycopy(sub, j + 1, newSub, j, sub.length - j - 1);
array[i] = newSub;
if (array[i].length == 0) emptyIndex = i;
found = true;
break;
}
}
if (found) break;
}
if (emptyIndex >= 0) {
long[][] newArray = new long[array.length - 1][];
System.arraycopy(array, 0, newArray, 0, emptyIndex);
System.arraycopy(array, emptyIndex + 1, newArray, emptyIndex, array.length - emptyIndex - 1);
array = newArray;
}
return array.length == 0 ? null : array;
}
此方法将从内部数组中删除给定的项目,如果内部数组为空,则将其从外部数组中删除。它返回修改后的数组,如果为空则返回null。
示例用法:
questionOrder = remove(questionOrder, 4);