【发布时间】:2017-10-02 12:14:50
【问题描述】:
我有一个数组如下:
public taskListCustom: any=[
{title: 'Task 1', status: 'done'},
{title: 'Task 2', status: 'done'},
{title: 'Task 3', status: 'done'},
{title: 'Task 4', status: 'done'},
{title: 'Task 5', status: 'done'},
{title: 'Task 6', status: 'done'},
{title: 'Task 7', status: 'done'},
{title: 'Task 8', status: 'done'},
{title: 'Task 9', status: 'done'},
{title: 'Task 10', status: 'done'},
{title: 'Task 11', status: 'done'},
{title: 'Task 12', status: 'done'},
{title: 'Task 13', status: 'done'},
{title: 'Task 14', status: 'done'},
{title: 'Task 15', status: 'done'},
{title: 'Task 16', status: 'done'},
{title: 'Task 17', status: 'done'},
{title: 'Task 18', status: 'done'},
{title: 'Task 19', status: 'done'},
{title: 'Task 20', status: 'done'},
{title: 'Task 21', status: 'done'},
{title: 'Task 22', status: 'done'},
{title: 'Task 23', status: 'done'},
{title: 'Task 24', status: 'done'},
]
还有一个空数组:public taskListCustomChunked: any=[];
我的目标是:如果我得到 6 的块大小(这个数字可以在 4 到 11 之间的任何位置),那么我必须将 taskListCustom 分成 6 个数组(即 24/6=4),然后将每个块插入为数组到 taskListCustomChunked 中,即它看起来像:
taskListCustomChunked = [[1,2,3,4],[5,6,7,8],[9,10,11,12],[13,14,15,16],[..],[..]]
我怎样才能完成它?
【问题讨论】:
-
如果是 5 那么 24/5 数组应该是什么样子?
-
如果剩余的元素不够,最后一个数组可以容纳更少的元素
标签: javascript arrays angular typescript