关于Javascript（数组）中的排行榜请帮助我答案

【问题标题】：About Leader Board in Javascript (Array) Help Me Please关于Javascript（数组）中的排行榜请帮助我
【发布时间】：2011-03-19 05:54:22
【问题描述】：

我需要关于我的游戏得分表的帮助。

-1- 我有 4 个变量：

var Player1Score= 44;
var Player2Score= 12;
var Player3Score= 45;
var Player4Score= 26;

--2-- 我做一个数组：

var MyArray=[Player1Score,Player2Score,Player3Score,Player4Score];

--3-- 对数组进行排序：

MyArray.Sort();

--4-- 打印：

---------高分----------

我的问题是：如何按顺序打印球员的姓名？

像这样：

---------高分----------

PLAYER 3              45

PLAYER 1              44

PLAYER 4              26

PLAYER 2              12

提前致谢。问候

【问题讨论】：

你看过我提出的答案吗？

标签： javascript arrays sorting

【解决方案1】：

这是一个显示它的 jsfiddle http://jsfiddle.net/q2Wkh/1/

我首先做了您发布的示例，没有任何重复，这只是有点棘手。您需要保留一张地图，其中显示哪些玩家有特定的得分

console.log("\n\n Without duplicates\n\n");
var Player1Score= 44;
var Player2Score= 12;
var Player3Score= 45;
var Player4Score= 26;
var MyArray = [Player1Score,Player2Score,Player3Score,Player4Score];

// Create a map of score to player number
var scoreToPlayerNumber = {};
for (var i=0; i < MyArray.length; i++) {
  // Add 1 since player 1 is slot 0
  scoreToPlayerNumber[MyArray[i]] = "Player " + (i + 1) ; 
}
// You wanna sort backwards
MyArray.sort(function(a,b){return b-a});

for (var i=0; i < MyArray.length; i++) {
    console.log (scoreToPlayerNumber[MyArray[i]] + " : " + MyArray[i]);
}

要处理重复得分，您的地图会跟踪哪个玩家得分，需要从得分到获得该得分的玩家列表。我还改进了变量名称，这有助于思考问题。

console.log("\n\n With duplicates\n\n");
var scores = [45, 43, 42, 48, 45];
var scoreToPlayerNumber = {};
for (var i=0; i < scores.length; i++) {
    var score = scores[i];
    if ( !scoreToPlayerNumber[score] ) {
        scoreToPlayerNumber[score] = [];
    }
    scoreToPlayerNumber[score].push("Player " + (i+1) );
}

scores.sort(function(a,b){return b-a});

// Some scores are in the list twice, don't print them twice
var seenScores = {};
for (var i=0; i < scores.length; i++) {
  var score = scores[i];
  if (!seenScores[score]) {
      var scorePlayers = scoreToPlayerNumber[score];
      for (var j = 0; j < scorePlayers.length; j++) {
         console.log(scorePlayers [j] + " : " + scores[i])
      }           
  }
  seenScores[score] = true;
}

最后。您正在使用的结构可以改进为更加灵活。这是一种更简单的方法，可以以不同的方式处理它；

var players = [
  {name: "Player 1", score: 45},
  {name: "Player 2", score: 41},
  {name: "Player 3", score: 46},
  {name: "Player 4", score: 44},
  {name: "Player 5", score: 45},
  {name: "Player 6", score: 43},
  {name: "Player 7", score: 48}
];

players.sort(function(a,b){ return b.score - a.score});

for (var i=0, player; player = players[i]; i++) {
    console.log(player.name + " : " + player.score);
}

【讨论】：