在 JSON 中将两个数组组合成一个对象答案

【问题标题】：Combine two arrays into an object in JSON在 JSON 中将两个数组组合成一个对象
【发布时间】：2014-08-18 20:53:11
【问题描述】：

column_names: [
    "School Year Ending",
    "Total Students",
    "American Indian/Alaskan Native: Total",
    "American Indian/Alaskan Native: Male",
    "American Indian/Alaskan Native: Female",
    "Asian/Pacific Islander: Total",
    "Asian/Pacific Islander: Male",
    "Asian/Pacific Islander: Female",
    "Hispanic: Total",
    "Hispanic: Male",
    "Hispanic: Female",
    "Black: Total",
    "Black: Male",
    "Black: Female",
    "White: Total",
    "White: Male",
    "White: Female"
],
data: [
    "2011-12-31",
    3471888,
    39433,
    19926,
    19507,
    182697,
    94104,
    88593,
    686081,
    344910,
    341171,
    536271,
    260720,
    275551,
    1970983,
    1006592,
    964391
]

有没有办法将这两个 JSON 数组转换为对象格式？例如：

"School Year Ending": "2011-12-31",
"Total Students": 3721888,
...

为了方便起见，我更喜欢使用 lo-dash 函数。有这样的吗？

【问题讨论】：

请注意，您的示例不是 JSON。它看起来像一个 JS 数组/对象。我相信你的问题根本与 JSON 无关。
它确实是 Felix，我只是复制了部分 JSON 返回以显示在这里。这个结构很长一段时间都与问题无关，所以我拿了一个样本。
数据来自哪里并不重要。看起来您想将两个 JS 数组组合成一个 JS 对象。例如，您选择的答案也与 JSON 无关。

标签： javascript arrays json object lodash

【解决方案1】：

_.zipObject(column_names, data);

应该这样做。

【讨论】：

所有其他答案都有效，但这个答案是我要求的。

【解决方案2】：

使用原生 JavaScript - Fiddle

var column_names = [
    "School Year Ending",
    "Total Students",
    "American Indian/Alaskan Native: Total",
    "American Indian/Alaskan Native: Male",
    "American Indian/Alaskan Native: Female",
    "Asian/Pacific Islander: Total",
    "Asian/Pacific Islander: Male",
    "Asian/Pacific Islander: Female",
    "Hispanic: Total",
    "Hispanic: Male",
    "Hispanic: Female",
    "Black: Total",
    "Black: Male",
    "Black: Female",
    "White: Total",
    "White: Male",
    "White: Female"
],
data = [
    "2011-12-31",
    3471888,
    39433,
    19926,
    19507,
    182697,
    94104,
    88593,
    686081,
    344910,
    341171,
    536271,
    260720,
    275551,
    1970983,
    1006592,
    964391
],
obj = {};

for (var i = 0, l = column_names.length; i < l; i += 1) {
    obj[column_names[i]] = data[i]
}
console.log(obj);

【讨论】：

【解决方案3】：

是的。我相信这会在纯 JS 中完成。

var columns = { };
for (var i in column_names) 
    columns[column_names[i]] = data[i];

JSFiddle

【讨论】：

【解决方案4】：

还有另一个使用 vanilla JS 的解决方案！这使用 forEach

http://jsfiddle.net/w5f36jwd/

school_data = {
    column_names:
    [
        "School Year Ending",
        "Total Students",
        "American Indian/Alaskan Native: Total",
        "American Indian/Alaskan Native: Male",
        "American Indian/Alaskan Native: Female",
        "Asian/Pacific Islander: Total",
        "Asian/Pacific Islander: Male",
        "Asian/Pacific Islander: Female",
        "Hispanic: Total",
        "Hispanic: Male",
        "Hispanic: Female",
        "Black: Total",
        "Black: Male",
        "Black: Female",
        "White: Total",
        "White: Male",
        "White: Female"
    ],
    data:
    [
        "2011-12-31",
        3471888,
        39433,
        19926,
        19507,
        182697,
        94104,
        88593,
        686081,
        344910,
        341171,
        536271,
        260720,
        275551,
        1970983,
        1006592,
        964391
    ]
}

var new_object = {};

school_data.column_names.forEach(function(el, index, data_array){
    new_object[el] = school_data.data[index];
});

console.log(new_object);

【讨论】：