如何在 python 中对海龟进行碰撞检测？答案

【问题标题】：How do you make a collision detection for turtle in python?如何在 python 中对海龟进行碰撞检测？
【发布时间】：2021-01-12 14:52:49
【问题描述】：

我遇到了问题，当我使用代码时：

from turtle import Turtle, Screen

playGround = Screen()
playGround.screensize(500, 500)
playGround.title("Race")
x=0

run = Turtle("turtle")
run.speed("fastest")
run.color("blue")
run.penup()
run.setposition(250, 250)

follow = Turtle("turtle")
follow.speed("fastest")
follow.color("red")
follow.penup()
follow.setposition(-250, -250)

def k1():
    run.forward(10)

def k2():
    run.left(20)

def k3():
    run.right(45)

def k4():
    run.backward(20)


def follow_runner():
    if x==0:
        follow.setheading(follow.towards(run))
        follow.forward(0.7)
        playGround.ontimer(follow_runner, 10)
        
while 1==1:
    playGround.onkey(k1, "Up")  # the up arrow key
    playGround.onkey(k2, "Left")  # the left arrow key
    playGround.onkey(k3, "Right") #It's obvious  
    playGround.onkey(k4, "Down")

    playGround.listen()

    follow_runner()
    runx= run.xcor()
    runy= run.ycor()
    followx = follow.xcor()
    followy= follow.ycor()

    playGround.mainloop()
    if  runx==followx and runy==followy:
        playGround.clear()
        x=1

当follow touch touch运行时，它只是继续，这意味着代码失败了。
我想让它工作并使箭头键能够按住。你能帮助我吗？请不要关闭它。

【问题讨论】：

标签： python python-turtle

【解决方案1】：

如果您希望海龟在按键保持中移动，请使用onkeypress()。另外，请注意，不需要使用 while 循环。

这里用这个：

from turtle import Turtle, Screen
import turtle
playGround = Screen()
playGround.screensize(500, 500)
playGround.title("Race")
x=0

run = Turtle("turtle")
run.speed("fastest")
run.color("blue")
run.penup()
run.setposition(250, 250)


follow = Turtle("turtle")
follow.speed("fastest")
follow.color("red")
follow.penup()
follow.setposition(-250, -250)


def k1():
    run.forward(10)

def k2():
    run.left(20)

def k3():
    run.right(45)

def k4():
    run.backward(20)


def follow_runner():
    global x
    runx= run.xcor()
    runy= run.ycor()
    followx = follow.xcor()
    followy= follow.ycor()

    if x==0:
        follow.setheading(follow.towards(run))
        follow.forward(0.7)
        playGround.ontimer(follow_runner, 10)
    
    if int(runx) == int(followx) or int(runy) == int(followy):
       
        x=1
        playGround.clear()


playGround.onkeypress(k1, "Up")  # the up arrow key
playGround.onkeypress(k2, "Left")  # the left arrow key
playGround.onkeypress(k3, "Right") #It's obvious  
playGround.onkeypress(k4, "Down")


follow_runner()

playGround.listen()
playGround.mainloop()

【讨论】：