【发布时间】:2020-08-25 05:13:28
【问题描述】:
有 2 个 json 数组需要合并,但是 array_merge 不起作用
我已经搜索并发现了可以与 array_merge 真正合并的 json 数组
这是我在单独文件中的 json 数据:
{
"J": [
{
"a": "BAAB1",
"b": "English"
},
{
"a": "BAAB2",
"b": "1"
},
{
"a": "BAAB3",
"b": "L"
},
{
"a": "BAAB4",
"b": "Test1 ..."
},
{
"a": "BAAB5",
"b": "Test2 ..."
},
{
"a": "BAAB6",
"b": "Test3 ..."
}
]
}
还有:
{
"J": [
{
"a": "BAAR1",
"b": "T1"
},
{
"a": "BAAR2",
"b": "1"
},
{
"a": "BAAR3",
"b": "111111"
},
{
"a": "BAAR4",
"b": "3"
},
{
"a": "BAAR5",
"b": "3"
},
{
"a": "BAAR6",
"b": "222222"
}
]
}
我从服务器上的路径读取文件,然后对每个读取的文件使用 json_decode,然后使用 array_merge
我认为我的 json 数组的名称 ("J") 造成了问题
这是我的代码:
//
$mLanguageFileName = $mClass_GeneralFunctions_General->GetStringBetween($mReadFile,"^^^","^^^^");
$mLanguageFile_Address = $ServerRoot_base.'/LAN/'.$mLanguageFileName.'.json';
$mClass_GeneralFunctions_FileFunctions = new GeneralFunctions_FileFunctions();
$mJSONFile_Language_C = $mClass_GeneralFunctions_FileFunctions->ReadFile($mLanguageFile_Address);
//
$mThemeFileName_M0 = $mClass_GeneralFunctions_General->GetStringBetween($mReadFile,"^^^^","^^^^^");
$mThemeFile_M0_Address = $ServerRoot_base.'/M0T/'.$mThemeFileName_M0.'/'.$mThemeFileName_M0.'.json';
$mClass_GeneralFunctions_FileFunctions = new GeneralFunctions_FileFunctions();
$mJSONFile_M0_C = $mClass_GeneralFunctions_FileFunctions->ReadFile($mThemeFile_M0_Address);
//
$mJsonArr_M0_C = json_decode($mJSONFile_M0_C, true);
$mJsonArr_Language_C = json_decode($mJSONFile_Language_C, true);
echo "\n\nmerge ... ";
$L = sizeof($mJsonArr_M0_C["J"]);
for ($i = 0; $i< $L; $i++)
{
echo "\n\nmJsonArr_M0_C i = {$i} ";
echo "\nmJsonArr_M0_C a = {$mJsonArr_M0_C["J"][$i]["a"]} ";
echo "\nmJsonArr_M0_C b = {$mJsonArr_M0_C["J"][$i]["b"]} ";
}
$L = sizeof($mJsonArr_Language_C["J"]);
for ($i = 0; $i< $L; $i++)
{
echo "\n\nmJsonArr_Language_C i = {$i} ";
echo "\nmJsonArr_Language_C a = {$mJsonArr_Language_C["J"][$i]["a"]} ";
echo "\nmJsonArr_Language_C b = {$mJsonArr_Language_C["J"][$i]["b"]} ";
}
$mJsonArr_C_LanguageM0 = array_merge($mJsonArr_Language_C, $mJsonArr_M0_C);
for ($i = 0; $i< sizeof($mJsonArr_C_LanguageM0["J"]); $i++)
{
echo "\n\nmJsonArr_C_LanguageM0 i = {$i} ";
echo "\nmJsonArr_C_LanguageM0 a = {$mJsonArr_C_LanguageM0["J"][$i]["a"]} ";
echo "\nmJsonArr_C_LanguageM0 b = {$mJsonArr_C_LanguageM0["J"][$i]["b"]} ";
}
每个 json 数组的数据都是真实回显的,但合并数据只是 array_merge 中的第二个 json 数组 ($mJsonArr_M0_C)
我该如何解决这个问题?
【问题讨论】:
-
您的预期输出是什么?你看过
array_merge_recursive吗? -
那么一个数组有 12 个对象?或者合并 6 个对象的键?具体一点。
-
一个包含 12 个对象的数组
标签: php array-merge