根据条件在python中过滤列表[重复]

Question

我有以下实现，将 CSV 文件转换为一行 numpy 数组：

results = []
with open(file2) as csvfile:
    reader = csv.reader(csvfile, quoting=csv.QUOTE_NONNUMERIC) 
# change contents to floats
    for row in reader: # each row is a list
        results.append(row)
        print(numpy.percentile(results, perc, axis = None))
        perc_value = numpy.percentile(results, perc, axis = None)

现在的想法是，基于用户提供的返回某个值的百分位数 - 比如说 100，我想从数组中删除所有低于 100 的条目。

so example results is [1, 50, 200, 500, 1000, 2000]
perc_value = 100
end result should be [200, 500, 1000, 2000]

我尝试了多次尝试，但要么我收到一个布尔错误，要么是该条件不能应用于列表，有什么想法吗？

我尝试了以下操作：

       for i in range (len(results)):
           if results[i] > perc_value: results.pop(i)
       print (results)

错误信息： ValueError：具有多个元素的数组的真值不明确。使用 a.any() 或 a.all()

Answer 1

有时人们认为复杂...保持简单并在流程的早期选择...

行 = 字符串。

# arbitrary taken selector values and char.
key      = 100 
position = 4
splitter = '.'

for row in reader: # row as a string.

    # preprocess input
    string_row = str(row)
    row_data = string_row.split (splitter)

    if int(row_data[position]) == key: # selection is done here

        results.append(row)
        print(numpy.percentile(results, perc, axis = None))
        perc_value = numpy.percentile(results, perc, axis = None)

行 = 带有变量的列表：

# arbitrary taken selector values and char.
key      = 100 
position = 4
splitter = '.'

for row in reader: # each row is a list

    if int(row[position]) == key: # selection is done here

        results.append(row)
        print(numpy.percentile(results, perc, axis = None))
        perc_value = numpy.percentile(results, perc, axis = None)