比较数组和嵌套循环答案

【问题标题】：Comparing Arrays with nested loops比较数组和嵌套循环
【发布时间】：2013-07-06 12:25:14
【问题描述】：

我正在尝试将两个数组的值相互比较。如果找到匹配项 - 执行某项操作 - 否则执行此操作。

如果您取消注释第 14 行的第二个警报，您将看到问题所在。我似乎无法阻止第二个警报触发。

谢谢！

var getkeywords = ["John","Frank","Sarah"]; 
var captionarray = ["Jim","Joe","Lee","Steve","John","Michelle","Brad"];    

for (k = 0; k < getkeywords.length; k++) {
    for (l = 0; l < captionarray.length; l++) {

    if(getkeywords[k] == captionarray[l]){

        alert('Found > ' + getkeywords[k] + ':filter image');

    }else{

        //alert('not found > ' + getkeywords[k] + ':filter image');

    }
  }
}

【问题讨论】：

标签： javascript arrays

【解决方案1】：

内部循环的每次迭代都会测试 if/else。我认为您所追求的是测试您是否有匹配 after 内部循环已运行。比如：

var getkeywords = ["John","Frank","Sarah"]; 
var captionarray = ["Jim","Joe","Lee","Steve","John","Michelle","Brad"];    
var matchFound;

for (k = 0; k < getkeywords.length; k++) {
    matchFound = false;

    for (l = 0; l < captionarray.length; l++) {
        if (getkeywords[k] == captionarray[l]){
            matchFound = true;
            break;
        }
    }

    if(matchFound){

        alert('Found > ' + getkeywords[k] + ':filter image');

    }else{

        alert('not found > ' + getkeywords[k] + ':filter image');

    }
}

【讨论】：

【解决方案2】：

我创建了一个新的小提琴：-

http://jsfiddle.net/WZGyy/

var getkeywords = ["John","Frank","Sarah"]; 
var captionarray = ["Jim","Joe","Lee","Steve","John","Michelle","Brad"];    

imagecode = '';
var found=0;
for (k = 0; k < getkeywords.length; k++) 
{
    for (l = 0; l < captionarray.length; l++) 
    {

        if(getkeywords[k] == captionarray[l])
        {


            found=1;
            break;

        }
    }

    if(found==1)
    {
        alert('Found > ' + getkeywords[k] + ':filter image');
        found=0;  


    }
    else
    {
        alert('not found > ' + getkeywords[k] + ':filter image');

    }
}

希望对您有所帮助..

【讨论】：

谢谢阿宾西特。非常感谢！

【解决方案3】：

在提醒结果之前，您必须将值与第二个数组中的所有项目进行比较我更新了你的 jsfiddle — 试试 http://jsfiddle.net/ZvmHx/5/

var getkeywords = ["John","Frank","Sarah"]; 
var captionarray = ["Jim","Joe","Lee","Steve","John","Michelle","Brad"];    

imagecode = '';
for (k = 0; k < getkeywords.length; k++) {
    var isExists = false;
    for (l = 0; l < captionarray.length; l++) {
        if (getkeywords[k] == captionarray[l]){                     
            isExists = true;
            break;
        }
    }

    if (isExists) {
        alert('Found > ' + getkeywords[k] + ':filter image');
    } else {
        alert('not found > ' + getkeywords[k] + ':filter image');
    }
}

【讨论】：