【问题标题】:Spark UnaryTransformer implementation fails with scala.MatchErrorSpark UnaryTransformer 实现因 scala.MatchError 而失败
【发布时间】:2017-07-21 12:34:38
【问题描述】:

我正在 Spark 1.6.2 中实现 UnaryTransformer。使用这个界面:

class myUT(override val uid: String) extends UnaryTransformer[Seq[String], Seq[String], myUT] {
...
override protected def createTransformFunc: Seq[String] => Seq[String] = {
   _ => _.map(x => x + "s")
}

这编译得很好,但在运行时返回一个错误:

17/07/21 22:29:33 WARN TaskSetManager: Lost task 0.3 in stage 0.0 (TID 3, myhost.com.au): scala.MatchError: ArrayBuffer(<contents of my array>) (of class scala.collection.mutable.ArrayBuffer)
at org.apache.spark.sql.catalyst.CatalystTypeConverters$StringConverter$.toCatalystImpl(CatalystTypeConverters.scala:295)
    at org.apache.spark.sql.catalyst.CatalystTypeConverters$StringConverter$.toCatalystImpl(CatalystTypeConverters.scala:294)
    at org.apache.spark.sql.catalyst.CatalystTypeConverters$CatalystTypeConverter.toCatalyst(CatalystTypeConverters.scala:102)
    at org.apache.spark.sql.catalyst.CatalystTypeConverters$$anonfun$createToCatalystConverter$2.apply(CatalystTypeConverters.scala:401)
    at org.apache.spark.sql.catalyst.expressions.GeneratedClass$SpecificUnsafeProjection.apply(Unknown Source)
    at org.apache.spark.sql.execution.Project$$anonfun$1$$anonfun$apply$1.apply(basicOperators.scala:51)
    at org.apache.spark.sql.execution.Project$$anonfun$1$$anonfun$apply$1.apply(basicOperators.scala:49)

接下来我尝试的是替换

_ => _.map(x => x + "s")

_ => _

所以,理论上这应该意味着数据完全没有变化!但我遇到的错误是:

17/07/21 22:11:59 WARN TaskSetManager: Lost task 0.0 in stage 0.0 (TID 0, myhost.com.au): scala.MatchError: WrappedArray(<contains of my array>) (of class scala.collection.mutable.WrappedArray$ofRef)
at org.apache.spark.sql.catalyst.CatalystTypeConverters$StringConverter$.toCatalystImpl(CatalystTypeConverters.scala:295)
    at org.apache.spark.sql.catalyst.CatalystTypeConverters$StringConverter$.toCatalystImpl(CatalystTypeConverters.scala:294)
    at org.apache.spark.sql.catalyst.CatalystTypeConverters$CatalystTypeConverter.toCatalyst(CatalystTypeConverters.scala:102)
    at org.apache.spark.sql.catalyst.CatalystTypeConverters$$anonfun$createToCatalystConverter$2.apply(CatalystTypeConverters.scala:401)
    at org.apache.spark.sql.catalyst.expressions.GeneratedClass$SpecificUnsafeProjection.apply(Unknown Source)
    at org.apache.spark.sql.execution.Project$$anonfun$1$$anonfun$apply$1.apply(basicOperators.scala:51)
    at org.apache.spark.sql.execution.Project$$anonfun$1$$anonfun$apply$1.apply(basicOperators.scala:49)

所以看起来传出数据的类型无论如何都会发生变化。我该如何避免这种情况?

更新:接下来我尝试将 .toArray 添加到地图中。现在的错误是这样的:

[error] /sparkprj/src/main/scala/sp_txt.scala:43: polymorphic expression cannot be instantiated to expected type;
[error]  found   : [B >: String]Array[B]
[error]  required: Seq[String]
[error]                                           ).toArray

它可能会增加一些细节,但不会增加我的理解。在查看了一些 mllib UnaryTransformer 的示例后,我倾向于认为这是 Catalyst 中的一个错误。

【问题讨论】:

    标签: scala apache-spark apache-spark-mllib


    【解决方案1】:

    myUT 类定义中的这一行不正确:

    override protected def outputDataType: DataType = new ArrayType(StringType, true)
    

    当我从 String->String 转换器复制这个类定义时,我将 DataType 定义为 StringType。我的错。

    【讨论】:

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