打印返回的数组 java

Question

你好，这是我的第一篇文章。 如果没有在正确的部分询问，我很抱歉，但我在完成这项作业时遇到了麻烦。我应该编写一个方法，在一个一维数组中返回 5 个计算。 一旦我尝试打印它，它就会为数组的每个元素打印 0.0 的值。我相信我可能无法将我想要的值输入到返回的数组中，但我不确定。有谁知道如何解决这个问题？

Scanner input = new Scanner(System.in);
        System.out.println("Please enter 5 numbers: ");
        double [] numbers = new double[5];
        double [] answers = calculations(numbers);

        for(int i = 0; i<numbers.length; i++){
            numbers[i] = input.nextDouble();
        }

        System.out.println("the maximum of the five numbers is: " + answers[0]);
        System.out.println("the minimum of the five numbers is: " + answers[1]);
        System.out.println("the average of the five numbers is: " + answers[2]);
        System.out.println("the standard deviation of the five numbers is: " + answers[3]);
        System.out.println("the sum of the five numbers is: " + answers[4]);

    }

    public static double[] calculations(double []numbers){
        double[] answers = new double[5];
        double max = numbers[1];
        double min = numbers[1];
        double sum = 0;

        //find max
        for(int i = 0; i<numbers.length; i++){
            if (numbers[i] > max) max = numbers[i];  
        }
        answers[0] = max;

        //find min
        for(int i = 0; i<numbers.length; i++){
            if (numbers[i] < min) min = numbers[i];  
        }
        min = answers[1];

        //find sum
        for(int i = 0; i<numbers.length; i++){
            sum = numbers[i] + sum;
            }
         answers[4] = sum;

        //find average
        double average = (sum / numbers.length);
         answers[2] = average;

        //find standard dev

        double sumOfSquared = 0;
        for(int i = 0; i<numbers.length; i++){
            sumOfSquared = sumOfSquared + Math.pow((numbers[i] - average),2);
        }
        double standarDev = Math.pow((sumOfSquared/numbers.length), .5);
         answers[3] = standarDev;

        return answers;
    }

}

Answer 1

在得到输入后考虑进行计算

    double [] answers = calculations(numbers);

    for(int i = 0; i<numbers.length; i++){
        numbers[i] = input.nextDouble();
    }

到

    for(int i = 0; i<numbers.length; i++){
        numbers[i] = input.nextDouble();
    }

    double [] answers = calculations(numbers);

Answer 2

除了上面提到的用户puj，把“find-min”这部分改一下：

min = answers[1];

到

answers[1] = min;

否则，您将始终得到 0.0 作为最小值。