php mysql 打印月份和表格内容

Question

我需要制作一个打印月份以及是否已付款的列表。

所以首先我创建了一个包含月份名称的数组：

$month_names = array("January","February","March","April","May","June","July","August","September","October","November","December");

然后我有十二个月的列：值 1 表示付费 0 表示未付费。所以我做了一个变量来知道它是否被支付：

if ($row['month1'] == '1') {
    $row['month1'] = 'Paid';
} else $row['month1'] = 'Non-Paid';

有没有更好的方法来做到这一点？

该列表将只有两列：“每月付款”和“状态”。

while 或 foreach 应该是这样的：

echo '
    <li><a class="months">'$array[$month_names]=>$value'</a></li>
    <li><a class="status">'.$row['month1'].'</a></li>
    ';

我不太确定，我该怎么做？

谢谢！

Answer 1

如果我没听错的话，你有一个这样的数组：

$rows = array(
    array('month' => 1, 'paid' => 0),
    array('month' => 2, 'paid' => 1),
    array('month' => 4, 'paid' => 0),
    array('month' => 5, 'paid' => 1),
    array('month' => 7, 'paid' => 1),
    array('month' => 8, 'paid' => 0),
);

在这种情况下，你可以这样做

<ul class="rows">
    <?php foreach ($rows as $row): ?>
        <li><a href="#" class="month"><?php echo $month_names[$row['month']] ?></a></li>
        <li><a href="#" class="status"><?php echo $row['paid'] ? 'Paid' : 'Non-Paid' ?></a></li>
    <?php endforeach ?>
</ul>

---

那会很理想，但我注意到您的示例数组有一个 month1 键，所以如果您的数组具有这种结构：month[0-9] = paid-status:

$rows = array(
    'month1' => 0,
    'month2' => 1,
    'month4' => 0,
    'month5' => 1,
    'month7' => 1,
    'month8' => 0,
);

那么你应该这样做：

<ul class="rows">
    <?php foreach ($rows as $month => $status): ?>
        <!-- We replace all non-numeric caracters in the key of the element and then sustract one to match the zero base index -->
        <li><a href="#" class="month"><?php echo $month_names[ preg_replace('/[^0-9]/', '', $month) - 1 ] ?></a></li>
        <li><a href="#" class="status"><?php echo $status ? 'Paid' : 'Non-Paid' ?></a></li>
    <?php endforeach ?>
</ul>

Answer 2

您在正确的轨道上保持逻辑与演示文稿分开。这是一件好事。对于您的问题，您可以检查所有月份值并将结果存储在另一个数组中（我们称之为$paid），按月份编号进行索引。然后使用$monthNames 数组映射到$paid 中的相应值。这将设置您循环遍历 $monthNames 数组并创建您的 HTML。

以下内容将满足您的需求：

<?php

$monthNames = array("January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November","December");
$paid = array(); //Placeholder for paid months.
$row = $result->fetch_array();  //Assuming MySQLi API (you are using that or PDO...I hope...)

for($i = 1; $i < 13; $i++) {
    $month = "month" . $i;
    if($row[$month] == 1) {
        $paid[] = "Paid";
    } else {
        $paid[] = "Not Paid";
    }
}

//Now make the HTML list

print("<ul>\n");
foreach($monthNames as $key => $month) {
    print('<li><a class="months">' . $month . '</a></li>' . "\n");
    print('<li><a class="status">' . $paid[$key] .'</a></li>' . "\n");
}
print("</ul>");

?>

输出将沿线（取决于数据库数据）：

<ul>
<li><a class="months">January</a></li>
<li><a class="status">Paid</a></li>
<li><a class="months">February</a></li>
<li><a class="status">Paid</a></li>
<li><a class="months">March</a></li>
<li><a class="status">Not Paid</a></li>
<li><a class="months">April</a></li>
<li><a class="status">Paid</a></li>
<li><a class="months">May</a></li>
<li><a class="status">Paid</a></li>
<li><a class="months">June</a></li>
<li><a class="status">Paid</a></li>
<li><a class="months">July</a></li>
<li><a class="status">Paid</a></li>
<li><a class="months">August</a></li>
<li><a class="status">Not Paid</a></li>
<li><a class="months">September</a></li>
<li><a class="status">Paid</a></li>
<li><a class="months">October</a></li>
<li><a class="status">Paid</a></li>
<li><a class="months">November</a></li>
<li><a class="status">Not Paid</a></li>
<li><a class="months">December</a></li>
<li><a class="status">Paid</a></li>
</ul>

希望有所帮助！