C++ 数组搜索和总结

Question

编辑：

我对我的代码进行了以下更改：

ifstream infile;

infile.open("sales.txt");

if ( !infile.is_open() ) cerr << "file didn't open" << endl;

if (!infile)
{
    cout << "Forget something?"
        << endl;
    return 1;
}

for(int i = 0; i < empl; i++)
    for(int j = 0; j < dps;  j++)
        cin >> data[i][j];

items = 0;
    for (row = 0; row < empl; row++)
    items = items + data[row][item];

money = 0;
    for (row = 0; row < dps; row++)
    money = money + data[row][sale];
taxes = 0;
    for (row = 0; row < empl; row++)
        taxes = taxes + data[row][tax];



itemsOne = 0;
itemsTwo = 0;
itemsThree = 0;
itemsFour = 0;
itemsFive = 0;

for(row = 0; row < dps; row++)
{
    if(idOne == data[row][ID])
    {
        itemsOne += data[row][item];
    }
    if(idTwo == data[row][ID])
    {
        itemsTwo += data[row][item];
    }
    if(idThree == data[row][ID])
    {
        itemsThree += data[row][item];
    }
    if(idFour == data[row][ID])
    {
        itemsFour += data[row][item];
    }
    if(idFive == data[row][ID])
    {
        itemsFive += data[row][item];
    }
}



cout << "***********************************" << endl;
cout << "Employee 100 sold : " << itemsOne << endl;
cout << "Employee 200 sold : " << itemsTwo << endl;
cout << "Employee 300 sold : " << itemsThree << endl;
cout << "Employee 400 sold : " << itemsFour << endl;
cout << "Employee 500 sold : " << itemsFive << endl;
cout << "***********************************" << endl;
cout << "Total items sold : " << items << endl;
cout << "Total revenue :" << revenue << endl;
cout << "Sales Tax: " << taxes << endl;
cout << "Gross Income: " << money << endl;
cout << "***********************************" << endl;
cout << "\n" << endl;
cout << "***********************************" << endl;
cout << "so long and thanks for all the fish" << endl;
cout << "***********************************" << endl;

system("pause");
return 0;   


system("pause");
return 0;
}

我已经手动检查了一个以旧方式放置的数组的逻辑，并且得到了 itemsFour、itemsFive 的零值，奇怪的是来自 500 子数组的销售数据没有通过。

所以我一直在做一个项目，遇到了一个绊脚石。我的目标是从以下文本文件中获取以下数组：

ID  Items Sales Tax
100 23    1200   110
200 12    7500   120
100 10    1000   230
300 11    1100   110
500 47    5800   122

并找出每个员工销售的物品、销售的总物品、总销售额和总税收。

这是只输出一系列零的代码：

#include <iostream>
#include <string>
#include <fstream>
#include <array>
#include <iomanip>
#include <cmath>

using namespace std;


const int empl = 5;
const int dps = 4;
float data [empl][dps];
int row;
int col;
double itemsOne, itemsTwo, itemsThree, itemsFour, itemsFive, items, revenue, taxes, money;
int item = 1, sale = 2, tax = 3;
float idOne = 100, idTwo = 200, idThree = 300, idFour = 400, idFive = 500;


int main()
{
ifstream infile;

infile.open("sales.txt");

infile >> data[empl][dps];


items = 0;
    for (col = 0; col < dps; col++)
    items = items + data[item][col];

taxes = 0;
    for (col = 0; col < dps; col++)
        taxes = taxes + data[tax][col];

money = 0;
        for (col = 0; col < dps; col++)
        money = money + data[sale][col];

itemsFour = 0;
for(col = 0; col < dps; col++)
{
    if(idOne = data[0][col])
    {
        itemsOne += data[1][col];
    }

    if(idTwo = data[0][col])
    {
        itemsTwo += data[1][col];
    }

    if(idThree = data[0][col])
    {
        itemsThree += data[1][col];
    }


    if(idFour = data [0][col])
    {
        itemsFour = itemsFour + data[1][col];
    }

    if(idFive = data[0][col])
    {
        itemsFive += data[1][col];
    }
}


revenue = money + taxes;


cout << "***********************************" << endl;      //Step 5 outputs report to command line
cout << "Employee 100 sold : " << itemsOne << endl;
cout << "Employee 200 sold : " << itemsTwo << endl;
cout << "Employee 300 sold : " << itemsThree << endl;
cout << "Employee 400 sold : " << itemsFour << endl;
cout << "Employee 500 sold : " << itemsFive << endl;
cout << "***********************************" << endl;
cout << "Total items sold : " << items << endl;
cout << "Total revenue :" << revenue << endl;
cout << "Sales Tax: " << taxes << endl;
cout << "Gross Income: " << money << endl;
cout << "***********************************" << endl;
cout << "\n" << endl;
cout << "***********************************" << endl;
cout << "so long and thanks for all the fish" << endl;
cout << "***********************************" << endl;

system("pause");
return 0;   


system("pause");
return 0;
}

Answer 1

您需要一些 for 循环来填充您的 data 数组。像这样的：

for (int i = 0; i < empl; i++)
    for (int j = 0; j < dps; j++)
        cin >> data[i][j];

请注意，如果您的数据文件像上面的示例一样包含标题，则需要在此循环之前读取并丢弃那些。像string temp; std::getline(cin, temp); 这样的东西就可以了。

我认为，在计算 items、taxes 和 money 的循环中，您已经切换了行和列。如果你的第一个索引是 empl，它是 0..4，那么你应该像这样切换它们：

items = 0;
for (row = 0; row < empl; row++)
    items = items + data[row][item];

我相信您也需要在后面的大循环中进行相同的切换。

最后，在这些语句中，您需要使用==，而不是= 来比较值：

if(idOne == data[0][col])  // use == here, not =
{
    itemsOne += data[1][col];
}

我没有详细审查您的代码逻辑，但如果您修复这些项目，您的状态会更好，可以进入下一步。