从 SQL Server 中的文本中提取数字

Question

我正在搜索脚本以从 sql server 中的文本中提取数字，我发现了这个

CREATE FUNCTION [dbo].[GetNumbersFromText](@String VARCHAR(2000))
RETURNS @Number TABLE (Number INT)
AS
BEGIN
DECLARE @Count INT
DECLARE @IntNumbers VARCHAR(1000)
SET @Count = 0
SET @IntNumbers = ''
WHILE @Count <= LEN(@String)
BEGIN
--Find a numeric charactor
IF SUBSTRING(@String,@Count,1) >= '0' AND SUBSTRING(@String,@Count,1) <= '9'
BEGIN
SET @IntNumbers = @IntNumbers + SUBSTRING(@String,@Count,1)
END
--If the next charactor is not a numeric one, the current number ends, so add a    separator
IF (SUBSTRING(@String,@Count+1,1) < '0'OR SUBSTRING(@String,@Count+1,1) > '9') AND    SUBSTRING(@String,@Count,1) >= '0' AND SUBSTRING(@String,@Count,1) <= '9'
BEGIN
SET @IntNumbers = @IntNumbers + ','
END
SET @Count = @Count + 1
END
---Split string to give a table with the numbers in the text
INSERT INTO @Number
SELECT DISTINCT items FROM dbo.Split(@IntNumbers, ',')
return
END

然后这样称呼它

SELECT Number FROM Dbo.[GetNumbersFromText]('Give me 120 this week and 50 next week')

它工作正常，但我需要更短的代码。我可以使用 patindex 从文本中提取数字吗？ 请任何人分享这样做的小而好的逻辑。谢谢

Answer 1

这有点短。将其变成使用递归 CTE 查找数字的内联表函数。

create function [dbo].[GetNumbersFromText](@String varchar(2000))
returns table as return
(
  with C as
  (
    select cast(substring(S.Value, S1.Pos, S2.L) as int) as Number,
           stuff(s.Value, 1, S1.Pos + S2.L, '') as Value
    from (select @String+' ') as S(Value)
      cross apply (select patindex('%[0-9]%', S.Value)) as S1(Pos)
      cross apply (select patindex('%[^0-9]%', stuff(S.Value, 1, S1.Pos, ''))) as S2(L)
    union all
    select cast(substring(S.Value, S1.Pos, S2.L) as int),
           stuff(S.Value, 1, S1.Pos + S2.L, '')
    from C as S
      cross apply (select patindex('%[0-9]%', S.Value)) as S1(Pos)
      cross apply (select patindex('%[^0-9]%', stuff(S.Value, 1, S1.Pos, ''))) as S2(L)
    where patindex('%[0-9]%', S.Value) > 0
  )
  select Number
  from C
)

如果您希望字符串中包含超过 100 个数字，则需要使用 option (maxrecursion 0) 调用它。

declare @S varchar(max)
set @S = 'Give me 120 this week and 50 next week'
select number from GetNumbersFromText(@S) option (maxrecursion 0)

Answer 2

@Vikram 的基本想法不错，但他们的查询会将所有数字作为单个项目返回。以下函数返回一个包含在源字符串中找到的单独数字的表：

CREATE FUNCTION dbo.GetNumbersFromText (@String varchar(2000))
RETURNS TABLE
AS
RETURN (
  WITH NumbersSplit AS (
    SELECT
      C = SUBSTRING(@String, number, 1),
      i = number,
      g = number - ROW_NUMBER() OVER (ORDER BY number)
    FROM master..spt_values
    WHERE type = 'P'
      AND SUBSTRING(@String, number, 1) BETWEEN '0' AND '9'
  ),
  NumbersAssembled AS (
    SELECT
      number = CAST(
        (SELECT C + '' FROM NumbersSplit WHERE g = g.g ORDER BY i FOR XML PATH (''))
        AS varchar(2000)
      )
    FROM NumbersSplit g
    GROUP BY g
  )
  SELECT * FROM NumbersAssembled
)

注意：此解决方案适用于 SQL Server 2005 或更高版本。

Answer 3

尝试以下逻辑：

declare @thestring varchar(50) 
set @thestring = 'Give me 120 this week and 50 next week' 
declare @final varchar(50) 
set @final = '' 

select @final = @final + x.thenum 
from 
( 
    select substring(@thestring, number, 1) as thenum, number 
    from master..spt_values 
    where substring(@thestring, number, 1) like '[0-9]' and type='P'
) x 
order by x.number 

print @final

Answer 4

-- 试试这个代码... -- 没关系！！！

---

CREATE FUNCTION [dbo].[udf_ExtractNumberFromString]
(
    @pInputString VARCHAR(MAX)
)
RETURNS VARCHAR(MAX)
AS
BEGIN

    DECLARE @OutputString varchar(MAX)=''
    DECLARE @string varchar(MAX)
    DECLARE @start INT
    DECLARE @end INT
    DECLARE @len INT

    SET @string=@pInputString
    --SET @string = 'the22478ddffafghrty12345TestAddressdd5aa789324-#345'
    SET @string = replace(@string, ' ' , '')

    WHILE PATINDEX('%[0-9]%',@string) <> 0
    BEGIN   
        SET @len = len(@string)
    --  PRINT @len

        set @start = PATINDEX('%[0-9]%',@string)
    --  PRINT @start

        SET @end= PATINDEX('%[^0-9]%',SUBSTRING(@string,@start,@len-@start))
    --  PRINT @end

        IF @end=0
            BEGIN
                SET @end=@len-@start
                SET @OutputString=SUBSTRING(@string,@start,@end+1)+'-'+@OutputString
                BREAK
            END
        ELSE 
            BEGIN 
                SET @OutputString=SUBSTRING(@string,@start,@end-1)+'-'+@OutputString
                SET @string=SUBSTRING(@string,@end+@start-1,@len-@end)
            END 

        --PRINT @string

        --PRINT @Output
        --PRINT '---------------------'
    END

    IF LEN(@OutputString)>0
        SET @OutputString=LEFT(@OutputString,LEN(@OutputString)-1) 
    --PRINT @OutputString

    RETURN @OutputString
END

Answer 5

这里是这个查询的合适且有效的解决方案

http://www.ittutorials.in/source/sql/sql-function-to-extract-only-numbers-from-string.aspx