按特定标识拆分python字符串[重复]答案

【问题标题】：Split a python string by particular identifications [duplicate]按特定标识拆分python字符串[重复]
【发布时间】：2020-06-02 01:03:50
【问题描述】：

我正在尝试在出现特定字符时拆分 python 字符串。

例如：

mystring="I want to eat an apple. \n 12345 \n 12 34 56"

我想要的输出是一个带有

的字符串

[["I want to eat an apple"], [12345], [12, 34, 56]]

【问题讨论】：

mystring.split('\n')

标签： python string split

【解决方案1】：

>>> mystring.split(" \n ")
['I want to eat an apple.', '12345', '12 34 56']

如果您特别希望每个字符串都包含在自己的列表中：

>>> [[s] for s in mystring.split(" \n ")]
[['I want to eat an apple.'], ['12345'], ['12 34 56']]

【讨论】：

【解决方案2】：

mystring = "I want to eat an apple. \n 12345 \n 12 34 56"
# split and strip the lines in case they all dont have the format ' \n '
split_list = [line.strip() for line in mystring.split('\n')] # use [line.strip] to make each element a list...
print(split_list)

输出：

['I want to eat an apple.', '12345', '12 34 56']

【讨论】：

【解决方案3】：

使用split()、strip() 和re 回答这个问题

先用nextline分割字符串，然后剥离它们，然后用re从字符串中提取数字，如果长度大于1则替换该项目

import re
mystring="I want to eat an apple. \n 12345 \n 12 34 56" 
l = [i.strip() for i in mystring.split("\n")]
for idx,i in enumerate(l):
  if len(re.findall(r'\d+',i))>1:
    l[idx] = re.findall(r'\d+',i)

print(l)
#['I want to eat an apple.', '12345', ['12', '34', '56']]

【讨论】：