如何在Ruby中将一个句子分成多个部分

Question

我想拆分一个主字符串，并用在 Ruby 中获得的单词创建多个字符串。

str = "one two three four five"

我想在一个字符串数组中创建所有这些可能性：

"one"
"one two"
"one two three"
"one two three four" 
"one two three four five" 

还有：

"two three four five"
"three four five"
"four five"
"five"

理想情况下，我也会获得里面的字符串，但不是必需的：

"two three four"
"two three"
"three four"

我尝试了很多东西，但很难找到最好的方法。

例如，我尝试使用 each_slice：

words = string.split(" ")
        number_of_words = words.length
        max_number_of_slices = number_of_words
        array_of_strings_to_match = []
        number_of_slices = 1
        while (number_of_slices <= max_number_of_slices)
          array = words.each_slice(number_of_slices).map do |a| a.join ' ' end
          array.each do |w| array_of_strings_to_match << w end
          number_of_slices = number_of_slices + 1
        end

但这不是好方法。

欢迎任何想法。 :-)

这个问题和this one有点不一样，因为我需要的是一个单词的句子，而不是一个字母的字符串（即使完全一样）。

Answer 1

str = "one two three four five".split
1.upto(str.size).flat_map { |i| str.each_cons(i).to_a }

#⇒ [["one"], ["two"], ["three"], ["four"], ["five"],
#   ["one", "two"], ["two", "three"], ["three", "four"], ["four", "five"],
#   ["one", "two", "three"], ["two", "three", "four"], ["three", "four", "five"],
#   ["one", "two", "three", "four"], ["two", "three", "four", "five"], 
#   ["one", "two", "three", "four", "five"]]

Answer 2

基于this answer的修改版本：

def split_words(string)
  words = string.split
  (0..words.length).inject([]) do |ai,i|
    (1..words.length - i).inject(ai) { |aj,j| aj << words[i,j] }
  end.map { |words| words.join(' ') }.uniq
end

用法

str = "one two three four five"

split_words(str)
#=> ["one",
#    "one two",
#    "one two three",
#    "one two three four",
#    "one two three four five",
#    "two",
#    "two three",
#    "two three four",
#    "two three four five",
#    "three",
#    "three four",
#    "three four five",
#    "four",
#    "four five",
#    "five"]