sql在分隔符上拆分5个值答案

【问题标题】：sql split 5 values on delimitersql在分隔符上拆分5个值
【发布时间】：2016-04-10 09:45:03
【问题描述】：

所以我有这段代码可以在双分隔符上精确分割 4 个值，它工作得很好，但我无法解决如何分割 5 个值这是我的字符串

@string = 'Value1|Value2|Value3|Value4|Value5, OtherVal1|OtherVal2|OtherVal3|OtherVal4|OtherVal5'

这是我用于拆分 4 个值的代码

WITH cte 
     AS (SELECT Replace(Rtrim(Ltrim(split.a.value('.', 'VARCHAR(100)'))), '|','.') AS split_data 
         FROM   (SELECT Cast ('<M>' + Replace(@string, ',', '</M><M>') 
                              + '</M>' AS XML) AS Data) AS A 
                CROSS apply data.nodes ('/M') AS Split(a)) 
SELECT COLUMN2= Parsename(split_data, 4), 
       COLUMN3=Parsename(split_data, 3), 
       COLUMN4= Parsename(split_data, 2), 
       COLUMN5=Parsename(split_data, 1) 
FROM   cte

如何将其拆分为 5 个 val？

【问题讨论】：

不就是加个 COLUMNX = Parsename(split_data, 5), ?
@Turo 没有。 parsename 只能使用 4 个部分。
您需要将字符串拆分为行，然后将拆分结果转为列。顺便说一句，这是另一个例子，为什么你不应该在 sql 中使用分隔数据。
@ZoharPeled 那我该怎么做呢？感谢您的宝贵时间
我很傻，但是您可以编写一个存储函数，根据需要使用分隔符和位置进行拆分

标签： sql string split common-table-expression delimiter

【解决方案1】：

乍一看...

看来，您必须使用CTE 两次。第一个 - 获取“行”（由, 分割数据）和第二个 - 获取“列”（由| 分割数据）。然后你必须PIVOT data 以表格形式显示它们;)

看看例子：

DECLARE @string VARCHAR(MAX) = 'Value1|Value2|Value3|Value4|Value5, OtherVal1|OtherVal2|OtherVal3|OtherVal4|OtherVal5'

;WITH MyRows AS
(
    SELECT 1 AS RowNo, LEFT(@string, CHARINDEX(', ', @string)-1) AS MyVals, RIGHT(@string, LEN(@string) - CHARINDEX(', ', @string)) AS Remainder
    WHERE CHARINDEX(', ', @string)>0
    UNION ALL
    SELECT RowNo + 1 AS RowNo, LEFT(Remainder, CHARINDEX(', ', Remainder)) AS MyVals, RIGHT(Remainder, LEN(Remainder) - CHARINDEX(', ', Remainder)) AS Remainder
    FROM MyRows
    WHERE CHARINDEX(', ', Remainder)>0
    UNION ALL
    SELECT RowNo + 1 AS RowNo, Remainder AS MyVals, NULL AS Remainder
    FROM MyRows
    WHERE CHARINDEX(', ', Remainder)=0
),
    MyCols AS
    (
        SELECT RowNo, 1 AS ColNumber,  LEFT(MyVals, CHARINDEX('|', MyVals)-1) AS SingleValue, RIGHT(MyVals, LEN(MyVals) - CHARINDEX('|', MyVals)) AS Remainder
        FROM MyRows 
        WHERE CHARINDEX('|', MyVals)>0
        UNION ALL
        SELECT RowNo, ColNumber + 1 AS ColNumber, LEFT(Remainder, CHARINDEX('|', Remainder)-1) AS SingleValue, RIGHT(Remainder, LEN(Remainder) - CHARINDEX('|', Remainder)) AS Remainder
        FROM MyCols
        WHERE CHARINDEX('|', Remainder)>0
        UNION ALL
        SELECT RowNo, ColNumber + 1 AS ColNumber, Remainder AS SingleValue, NULL AS Remainder
        FROM MyCols
        WHERE CHARINDEX('|', Remainder)=0
    )
SELECT RowNo, [1],[2],[3],[4],[5]
FROM (
    SELECT ColNumber, SingleValue, RowNo
    FROM MyCols ) AS DT
PIVOT(Max(SingleValue) FOR ColNumber IN([1],[2],[3],[4],[5])) AS PT

结果：

RowNo    1          2           3           4           5
1        Value1     Value2      Value3      Value4      Value5
2        OtherVal1  OtherVal2   OtherVal3   OtherVal4   OtherVal5

【讨论】：