T-SQL 中的拆分函数

Question

我有一个包含逗号分隔字符串的字段的表。我想创建返回以下结果的查询：

我想创建返回拆分文本的查询。例如：

表格中的数据：

| ID                                   | Names                            |
| ------------------------------------ | -------------------------------- |
| 63F5D993-3AC9-4EEA-8007-B669542BAD9A | John Smith,Kerry King,Tom Arraya |

要求的结果：

 ID                                   | Names                             
------------------------------------  | -----------
63F5D993-3AC9-4EEA-8007-B669542BAD9A  | John Smith                       
------------------------------------- | -----------
63F5D993-3AC9-4EEA-8007-B669542BAD9A  | Kerry King                       
------------------------------------- | -----------
63F5D993-3AC9-4EEA-8007-B669542BAD9A  | Tom Arraya  

我找到了 T-SQL 的“拆分”功能，但它的工作原理并不完全适合我的情况。我不能这样执行：

SELECT dbo.Split(dbo.name, ',') FROM dbo.Mytable

它只能执行如下：

SELECT * FROM dbo.Split('John Smith,Kerry King,Tom Arraya', ',')

但它不适合我。 我也尝试写光标：

DECLARE @bkb varchar(256)
DECLARE @Bkb_Cursor CURSOR 
SET @Bkb_Cursor = CURSOR SCROLL FOR  
SELECT bkb.best_know_by
  FROM  [sugarcrm_cmsru_dev].[dbo].[contacts] c
  left JOIN [dbo].[email_addr_bean_rel]  eb
  ON eb.[bean_id] = c.[id]
  JOIN [dbo].[email_addresses] ea
  ON ea.[id] = eb.[email_address_id]
  JOIN [dbo].[contacts_cstm] ccs
  ON eb.bean_id = ccs.id_c
  left JOIN [dbo].[BestKnowBy$] bkb
  ON c.[campaign_id] =bkb.Con_id
  where c.deleted = 0;  
OPEN @Bkb_Cursor;  
FETCH NEXT FROM @Bkb_Cursor
INTO @bkb;
WHILE @@FETCH_STATUS = 0
BEGIN  
      PRINT dbo.Splitfn(@bkb);
      FETCH NEXT FROM @Bkb_Cursor INTO @bkb;  
END
CLOSE @Bkb_Cursor;  
DEALLOCATE @Bkb_Cursor;  
GO

但它不起作用。我收到错误“此上下文中不允许列“dbo”，并且找不到用户定义的函数或聚合“dbo.Splitfn”。”

我该如何解决这个问题？

我的查询如下所示：

SELECT c.[id], 
       bkb.best_know_by
  FROM  [sugarcrm_cmsru_dev].[dbo].[contacts] c
  left JOIN [dbo].[email_addr_bean_rel]  eb
  ON eb.[bean_id] = c.[id]
  JOIN [dbo].[email_addresses] ea
  ON ea.[id] = eb.[email_address_id]
  JOIN [dbo].[contacts_cstm] ccs
  ON eb.bean_id = ccs.id_c
  left JOIN [dbo].[BestKnowBy$] bkb
  ON c.[campaign_id] =bkb.Con_id
  where c.deleted = 0; 

bkb.best_know_by 字段包含逗号分隔的字符串。在这种情况下如何使用“交叉申请”？

Answer 1

您需要将CROSS APPLY 与表格的结果集结合使用，该结果集将为每一行执行该函数：

SELECT st.ID, spl.value
FROM SplitTest st
CROSS APPLY string_split(st.Names, ',') spl

编辑： 关于将您的查询添加到您的问题，您可以执行以下操作：

;WITH CTE_Query AS (
    SELECT c.[id], 
       bkb.best_know_by
    FROM  [sugarcrm_cmsru_dev].[dbo].[contacts] c
    left JOIN [dbo].[email_addr_bean_rel]  eb
    ON eb.[bean_id] = c.[id]
    JOIN [dbo].[email_addresses] ea
    ON ea.[id] = eb.[email_address_id]
    JOIN [dbo].[contacts_cstm] ccs
    ON eb.bean_id = ccs.id_c
    left JOIN [dbo].[BestKnowBy$] bkb
    ON c.[campaign_id] =bkb.Con_id
    where c.deleted = 0
)
SELECT cte.id, spl.value
FROM CTE_Query AS cte
CROSS APPLY string_split(cte.best_know_by, ',') spl

Answer 2

交叉申请就可以了

Select A.ID
      ,Names = B.Item   -- << Return Field from your Split Function
 From  YourTable A
 Cross Apply (Select * from dbo.Split(A.Names, ',') ) B

您的查询

SELECT c.[id]
      ,S.*      --<< Removed bkb.best_know_by and Replaced with S.* (don't know your Split() Return Field)
 FROM  [sugarcrm_cmsru_dev].[dbo].[contacts] c
 LEFT JOIN [dbo].[email_addr_bean_rel]  eb ON eb.[bean_id] = c.[id]
 JOIN [dbo].[email_addresses] ea ON ea.[id] = eb.[email_address_id]
 JOIN [dbo].[contacts_cstm] ccs   ON eb.bean_id = ccs.id_c
 LEFT JOIN [dbo].[BestKnowBy$] bkb   ON c.[campaign_id] =bkb.Con_id
 Cross Apply dbo.Split(bkb.best_know_by,',')  S
 where c.deleted = 0;