【发布时间】:2017-11-18 20:34:07
【问题描述】:
您好,我有一个这样的 JSON 字符串:
{
"vidID": "CevxZvSJLk8",
"vidTitle": "Katy Perry - Roar (Official)",
"vidInfo": {
"0": {
"rSize": "67.79 MB",
"quality": "720",
"directurl": "https://r2---sn-5uh5o-f5f6.googlevideo.com/videoplayback?ipbits=0&mm=31&mn=sn-5uh5o-f5f6&itag=22&mt=1492837642&dur=269.165&id=o-AB1T_kZWIIiA_ihhSlAK4RXegp3Z9A18zn39hF0Aa51G&initcwndbps=197500&pl=21&source=youtube&mv=m&ip=137.74.1.176&mime=video%2Fmp4&ms=au&ratebypass=yes&requiressl=yes&sparams=dur%2Cei%2Cid%2Cinitcwndbps%2Cip%2Cipbits%2Citag%2Clmt%2Cmime%2Cmm%2Cmn%2Cms%2Cmv%2Cpl%2Cratebypass%2Crequiressl%2Csource%2Cupn%2Cexpire&key=yt6&lmt=1478841669593636&upn=Wp652d9rFKo&ei=OuX6WLqMDJaLNK-MmLAE&expire=1492859290&signature=A8B328D48101C553D0659D2D9D1F1B2F249D2035.792897E2CF6BFEFC97C81A90EA9CBF9B76FD0283&type=video%252Fmp4%253B%2Bcodecs%253D%2522avc1.64001F%252C%2Bmp4a.40.2%2522&quality=hd720&title=Katy%2BPerry%2B-%2BRoar%2B%2528Official%2529",
"dloadUrl": "//downloadmp.org/@download/22-58fae53acfc14-mp4-71087585/videos/CevxZvSJLk8/Katy%2BPerry%2B-%2BRoar%2B%2528Official%2529.mp4",
"ftype": "mp4",
"framerate": "",
"bitrate": "",
"codec": "",
"itag": "22",
"vidid": "CevxZvSJLk8"
}}}
我正在尝试获取直接 url 的价值。 所以这是我的 PHP 代码:
$obj = json_decode($json);
echo $obj->vidInfo[0]->directurl;
也试过了
echo $obj->vidInfo->0->directurl;
但我无法获取属性直接 url 的值。
【问题讨论】:
-
$obj = json_decode($json,true); echo $obj[0]['vidInfo'][0]['directurl']