将对象数组中两个属性的唯一值存储到单个数组中答案

【问题标题】：Store the unique values of two properties from array of objects into single array将对象数组中两个属性的唯一值存储到单个数组中
【发布时间】：2019-05-22 05:19:12
【问题描述】：

如何获取 requesterPractitionerId 和 performerOrganizationId 的唯一值。我需要在单个数组中查找 requesterPractitionerId 和 performerOrganizationId 的唯一值。

[ 
    { 
        id: '1043120',
        requesterPractitionerId: '1043119',
    },
    { 
        id: '1043081',
        requesterPractitionerId: '1043080'
    },
    { 
        id: 'e1dceebe-c5ba-46a5-a63a-bff709896af4',
        requesterPractitionerId: 'e0a844e4-6c8a-489a-8bd6-1d62267d311e',
        performerOrganizationId: '05D0889009',
    },
    { 
        id: '2709842f-41e3-4193-8607-fc34d3d24ec1',
        requesterPractitionerId: 'e0a844e4-6c8a-489a-8bd6-1d62267d311e',
        performerOrganizationId: '05D0889009'
    } 
]

预期输出：

1043119
1043080
e0a844e4-6c8a-489a-8bd6-1d62267d311e
05D0889009

我是 Javascript 新手，为此苦苦挣扎了几个小时。任何帮助都会非常感激。

【问题讨论】：

标签： javascript arrays ecmascript-6 set javascript-objects

【解决方案1】：

使用Set、Array.reduce 和Array.from

使用reduce 创建具有所述字段的唯一值的集合
然后使用Array.from 将集合转换为数组

let arr = [{id:'1043120',requesterPractitionerId:'1043119'},{id:'1043081',requesterPractitionerId:'1043080'},{id:'e1dceebe-c5ba-46a5-a63a-bff709896af4',requesterPractitionerId:'e0a844e4-6c8a-489a-8bd6-1d62267d311e',performerOrganizationId:'05D0889009'},{id:'2709842f-41e3-4193-8607-fc34d3d24ec1',requesterPractitionerId:'e0a844e4-6c8a-489a-8bd6-1d62267d311e',performerOrganizationId:'05D0889009'}];

let result = Array.from(arr.reduce((a,c) => {
  if(c.requesterPractitionerId) a.add(c.requesterPractitionerId);
  if(c.performerOrganizationId) a.add(c.performerOrganizationId);
  return a;
}, new Set()));

console.log(result);

【讨论】：

其实我是用do while循环来获取数据的。那么如何将数据存储在单个数组中并检查数组中的重复条目。你能检查一下代码吗？ pastebin.com/S7Sv6s1M
您需要将let newArry = []; 移到do-while 循环之外。有了它在循环中，对于每个循环，以前的循环值都会丢失
你能给我看看代码吗？请检查 pastebin 中的更新代码：pastebin.com/EPb8kBPp
ReferenceError: 记录未定义错误抛出
让我们continue this discussion in chat。

【解决方案2】：

一种解决方案是使用Array.reduce() 从您需要的属性中生成一个新的Set。之后，您可以spread 数组中的集合项。

const input = [{id:'1043120',requesterPractitionerId:'1043119'},{id:'1043081',requesterPractitionerId:'1043080'},{id:'e1dceebe-c5ba-46a5-a63a-bff709896af4',requesterPractitionerId:'e0a844e4-6c8a-489a-8bd6-1d62267d311e',performerOrganizationId:'05D0889009',},{id:'2709842f-41e3-4193-8607-fc34d3d24ec1',requesterPractitionerId:'e0a844e4-6c8a-489a-8bd6-1d62267d311e',performerOrganizationId:'05D0889009'}];

let res = input.reduce((acc, o) =>
{
    if (o.hasOwnProperty("requesterPractitionerId"))
        acc.add(o.requesterPractitionerId);

    if (o.hasOwnProperty("performerOrganizationId"))
        acc.add(o.performerOrganizationId);

    return acc;
}, new Set())

console.log([...res]);

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【讨论】：

其实我是用do while循环来获取数据的。那么如何将数据存储在单个数组中并检查数组中的重复条目

【解决方案3】：

您可以使用forEach 迭代data，然后使用Set 删除重复项

let data = [{
    id: '1043120',
    requesterPractitionerId: '1043119',
  },
  {
    id: '1043081',
    requesterPractitionerId: '1043080'
  },
  {
    id: 'e1dceebe-c5ba-46a5-a63a-bff709896af4',
    requesterPractitionerId: 'e0a844e4-6c8a-489a-8bd6-1d62267d311e',
    performerOrganizationId: '05D0889009',
  },
  {
    id: '2709842f-41e3-4193-8607-fc34d3d24ec1',
    requesterPractitionerId: 'e0a844e4-6c8a-489a-8bd6-1d62267d311e',
    performerOrganizationId: '05D0889009'
  }
]


let newArry = [];
data.forEach(function(item) {
  newArry.push(item.requesterPractitionerId);
  if (item.hasOwnProperty('performerOrganizationId')) {
    newArry.push(item.performerOrganizationId)
  }
})

let k = Array.from(new Set(newArry));

console.log(k)

【讨论】：

你能检查一下我在do while循环中写的代码吗？ pastebin.com/S7Sv6s1M 但我得到了不同的结果。

【解决方案4】：

真的很简单——Set 和 map、reduce 和 filter：

const arr = [{id:'1043120',requesterPractitionerId:'1043119',},{id:'1043081',requesterPractitionerId:'1043080'},{id:'e1dceebe-c5ba-46a5-a63a-bff709896af4',requesterPractitionerId:'e0a844e4-6c8a-489a-8bd6-1d62267d311e',performerOrganizationId:'05D0889009',},{id:'2709842f-41e3-4193-8607-fc34d3d24ec1',requesterPractitionerId:'e0a844e4-6c8a-489a-8bd6-1d62267d311e',performerOrganizationId:'05D0889009'}];
const res = [...new Set(arr.map(({ requesterPractitionerId, performerOrganizationId }) => [requesterPractitionerId, performerOrganizationId]).reduce((acc, curr) => acc.concat(curr)).filter(Boolean))];
console.log(res);

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【讨论】：