【发布时间】:2020-02-05 17:34:08
【问题描述】:
我正在为 TodoList 进行搜索过滤。
在 todoList 中,我使用了一个函数来渲染名为 renderItem 的项目,但是当我在 inputText 中写入搜索项目时,我不知道如何重新渲染
有人可以帮我吗?
StaticContainer.js
import * as React from 'react';
import { FlatList, Text, View, StyleSheet, TouchableOpacity, TextInput } from 'react-native';
export default class StaticCounter extends React.Component {
constructor(props) {
super(props);
this.state = {
filter: '',
name: '',
}
this.renderItem = this.renderItem.bind(this)
this.setState = this.setState.bind(this)
}
setState(text){
this.state.filter = text
alert(JSON.stringify(this.state.filter))
this.renderItem
}
renderItem(obj){
if (this.state.filter != '') {
if (obj.item.desc.startsWith(this.state.filter)) {
console.log(typeof(obj.item.desc));
let key = obj.item.key
return(
<TouchableOpacity style={styles.container} onPress={()=> this.props.acessarDados(key)}>
<Text style={styles.cel}>{obj.item.desc}</Text>
</TouchableOpacity>
)
}else{
}
}else{
let key = obj.item.key
return(
<TouchableOpacity style={styles.container} onPress={()=> this.props.acessarDados(key)}>
<Text style={styles.cel}>{obj.item.desc}</Text>
</TouchableOpacity>
)
}
}
render() {
return (
<View>
<FlatList style={styles.lista} data={this.props.itens} renderItem={this.renderItem}/>
<TextInput style={styles.input} onChangeText={(text) =>{this.setState(text)}}/>
</View>
);
}
}
const styles = StyleSheet.create({
container: {
flex: 1,
backgroundColor: '#fff',
justifyContent: 'center',
},
lista: {
marginTop: 90,
},
cel:{
paddingVertical: 20,
backgroundColor: '#E4EBEE',
fontSize: 18,
marginBottom: 2,
},
inputView:{
flexDirection: 'row',
alignItems: 'center',
justifyContent: 'space-between',
},
input:{
backgroundColor: '#fff',
borderColor: '#ccc',
borderWidth: 3,
padding: 15,
margin:20,
color: '#3d3d3d'
}
});
【问题讨论】:
标签: javascript reactjs react-native