根据B 沿k-th 维度对A 进行排序:如果您的数据不复杂,一个简单的方法是:
- 将
A 和B 打包成一个复数数组,其中A 是虚部,B 是实部;
- 根据实部沿
k-th 维度排序;
- 保留虚部。
这是在一行中完成的,如下所示:
result = imag(sort(B+1j*A, k, 'ComparisonMethod', 'real'));
示例:
>> A = rand(2,4,3)
A(:,:,1) =
0.162182308193243 0.311215042044805 0.165648729499781 0.262971284540144
0.794284540683907 0.528533135506213 0.601981941401637 0.654079098476782
A(:,:,2) =
0.689214503140008 0.450541598502498 0.228976968716819 0.152378018969223
0.748151592823709 0.083821377996933 0.913337361501670 0.825816977489547
A(:,:,3) =
0.538342435260057 0.078175528753184 0.106652770180584 0.004634224134067
0.996134716626885 0.442678269775446 0.961898080855054 0.774910464711502
>> B = randi(9, size(A))
B(:,:,1) =
8 1 3 4
8 4 8 9
B(:,:,2) =
2 2 8 5
3 2 6 2
B(:,:,3) =
8 4 4 3
6 5 1 2
>> k = 2;
>> result = imag(sort(B+1j*A, k, 'ComparisonMethod', 'real'))
result(:,:,1) =
0.311215042044805 0.165648729499781 0.262971284540144 0.162182308193243
0.528533135506213 0.601981941401637 0.794284540683907 0.654079098476782
result(:,:,2) =
0.450541598502498 0.689214503140008 0.152378018969223 0.228976968716819
0.083821377996933 0.825816977489547 0.748151592823709 0.913337361501670
result(:,:,3) =
0.004634224134067 0.078175528753184 0.106652770180584 0.538342435260057
0.961898080855054 0.774910464711502 0.442678269775446 0.996134716626885