【发布时间】:2022-01-23 11:05:27
【问题描述】:
我正在尝试通过 flask-socketio 使用后台任务并遇到两个问题:
- 在重新加载模式下,后台任务启动两次
- 更改代码时,flask 会重新加载,但不会终止后台任务
我的代码:
from flask import Flask
from flask_socketio import SocketIO
import random
application = Flask(__name__)
socketio = SocketIO(application, async_mode='eventlet')
import eventlet
eventlet.monkey_patch()
def background_thread():
print('starting backgound task')
thread_id = random.randint(1,100)
while True:
print(f'background thread {thread_id}')
socketio.sleep(1)
if __name__ == '__main__':
print('--------------------')
socketio.start_background_task(background_thread)
socketio.run(application, debug=True, use_reloader=True)
输出:
python application.py
--------------------
starting backgound task
background thread 26
* Restarting with stat
--------------------
starting backgound task
background thread 59
background thread 26
* Detected change in '/Users/philipp/code/nifmap/application.py', reloading
background thread 26
background thread 59
background thread 26
background thread 59
当我然后点击^C 然后一个后台任务被杀死,但不是另一个。仅当我执行debug=True 时才会发生这种情况。如何启动后台任务,使其仅启动一次,然后在重新加载时终止?
在使用 gevent 时也会发生同样的情况,从 async_mode='eventlet' 开始并执行以下操作:
from gevent import monkey
monkey.patch_all()
版本:
eventlet==0.33.0
Flask==2.0.2
Flask-SocketIO==5.1.1
Flask-WTF==0.15.1
greenlet==1.1.2
python-engineio==4.3.0
python-socketio==5.5.0
websocket-client==1.2.3
Werkzeug==2.0.2
Python 3.8.2
【问题讨论】:
标签: python-3.x socket.io flask-socketio eventlet