【发布时间】：2016-02-23 20:54:46
【问题描述】：
我相信这个问题的答案应该很简单。我从某个地方获取目录列表并将它们存储到文本文档中。然后我读取文本文档名称并将它们存储到一个数组中。在此过程结束时，我希望擦除数组中的所有条目。
我想这样做的原因是因为我要遍历几个文件夹位置并将它们存储到同一个数组中。但是，当我每次都不清除数组时，当我稍后尝试将其打印出来时，它似乎给了我各种各样的麻烦。
每次我去填写下一个文件夹时，我都需要一个新的数组。
REM **************************************************************************
REM this part needs to delete the value but doesnt
set !array[%arraywiper%]!=0
REM **************************************************************************
这是我遇到的问题的一个示例。可以运行下面的代码来看看我在说什么。
ECHO OFF & setLocal EnableDELAYedExpansion
cls
REM creates folder for text doc
IF EXIST "c:\TEMP" (echo.) else (md c:\TEMP\)
REM Scans C:\Program Files (x86) and stores into a text doc
(for /f "delims=" %%a in ('dir /a:D-H-S /on /b "C:\Program Files (x86)"') do echo %%a)> c:\TEMP\dork_array_wipe.txt
REM Counts the folders in the text doc
for /d %%a in ("C:\Program Files (x86)\"*) do (
set /a locationcount+=1
)
REM Stores the values from the doc into an array
for /F "usebackq delims=" %%a in ("c:\TEMP\dork_array_wipe.txt") do (
set /A i+=1
call set array[%%i%%]=%%a
)
set arraywiper=1
:Arraywipeloop19
IF %arraywiper%==%locationcount% GOTO Arraywipecomplete19 else (
REM Prints array to show value entered array
echo array (%arraywiper%): !array[%arraywiper%]!
REM **************************************************************************
REM this part needs to delete the value but doesnt
set !array[%arraywiper%]!=0
REM **************************************************************************
Set /a arraywiper+=1
REM Prints out array in question to veryify change took place
echo array (%arraywiper%): !array[%arraywiper%]!
GOTO Arraywipeloop19
)
:Arraywipecomplete19
pause
先生。 Rojo 给了我一个很好的解决这个问题的方法。这是其工作原理的一个示例。
@echo off
setlocal
set "array[0]=foo"
set "array[1]=bar"
set "array[2]=baz"
set "array[3]=qux"
set "array[4]=quux"
set "array[5]=corge"
echo.
echo first printout
echo %array[0]%, %array[1]%, %array[2]%, %array[3]%, %array[4]%, %array[5]%
pause
rem // starting with element 3, delete 2 elements and insert 3 new
call :splice array 3 2 grault garply waldo
echo.
echo second printout
echo %array[0]%, %array[1]%, %array[2]%, %array[3]%, %array[4]%, %array[5]%, %array[6]%, %array[7]%
pause
call :splice array 0
REM set array[
REM goto :EOF
echo.
echo third printout
echo %array[0]%, %array[1]%, %array[2]%, %array[3]%, %array[4]%, %array[5]%, %array[6]%
pause
set "array[0]=foo"
set "array[1]=bar"
set "array[2]=baz"
set "array[3]=qux"
set "array[4]=quux"
set "array[5]=corge"
echo.
echo fourth printout
echo %array[0]%, %array[1]%, %array[2]%, %array[3]%, %array[4]%, %array[5]%, %array[6]%
pause
:splice <array_name> <startIDX> [<deleteCount> [<item1> [<item2> [...]]]]
rem // works like JavaScript Array.prototype.splice()
rem // https://developer.mozilla.org/en-US/search?q=Array.prototype.splice()
setlocal enabledelayedexpansion
set /a idx = 0, argskip = 0, inserted = 0, orig_ubound = -1
if "%~3"=="" (set /a "resume = 1 << 30") else set /a resume = %~2 + %~3
for /f "tokens=1* delims==" %%I in ('set %~1[') do (
set /a orig_ubound += 1
if !idx! lss %~2 (
set "tmp[!idx!]=%%J"
set /a ubound = idx, idx += 1
) else (
if !inserted! equ 0 (
for %%# in (%*) do (
set /a argskip += 1, inserted = 1
if !argskip! gtr 3 (
set "tmp[!idx!]=%%~#"
set /a ubound = idx, idx += 1, resume += 1
)
)
)
if !idx! geq !resume! (
set "tmp[!idx!]=%%J"
set /a ubound = idx, idx += 1
) else set /a resume -= 1
)
)
set "r=endlocal"
for /f "tokens=1* delims=[" %%I in ('2^>NUL set tmp[') do (
set "r=!r!&set "%~1[%%J""
)
for /L %%I in (%idx%,1,%orig_ubound%) do set "r=!r!&set "%~1[%%I]=""
%r%&exit/b
【问题讨论】：
-
去掉
!s 中的set语句。 -
setlocal在构建阵列之前。只需执行set array即可输出所有数组值。当你想销毁数组时，endlocal. -
@SomethingDark 摆脱！的除了破坏代码什么也没做。如果我删除！的代码不再输出任何东西。我尝试只删除数组清除部分中的 !，但它什么也没做。
-
@rojo 我不完全明白你要我做什么。举个例子会很有帮助。
标签： arrays batch-file