【发布时间】:2015-10-28 16:38:04
【问题描述】:
我正在尝试让我们 knitr 使用 xtable 以表格格式打印数据框:
```{r xtable,fig.width=10, fig.height=8, message=FALSE, results = 'asis', echo=FALSE, warning=FALSE, fig.cap='long caption', fig.scap='short',tidy=FALSE}
print(xtable(d),format="markdown")
```
这是d的数据框:
d <- structure(list(Hostname = structure(c(8L, 8L, 9L, 5L, 6L, 7L,
1L, 2L, 3L, 4L), .Label = c("db01", "db02", "farm01", "farm02",
"tom01", "tom02", "tom03", "web01", "web03"), class = "factor"),
Date = structure(c(6L, 10L, 5L, 3L, 2L, 1L, 8L, 9L, 7L, 4L
), .Label = c("10/5/2015 1:15", "10/5/2015 1:30", "10/5/2015 2:15",
"10/5/2015 4:30", "10/5/2015 8:30", "10/5/2015 8:45", "10/6/2015 8:15",
"10/6/2015 8:30", "9/11/2015 5:00", "9/11/2015 6:00"), class = "factor"),
Cpubusy = c(31L, 20L, 30L, 20L, 18L, 20L, 41L, 21L, 29L,
24L), UsedPercentMemory = c(99L, 98L, 95L, 99L, 99L, 99L,
99L, 98L, 63L, 99L)), .Names = c("Hostname", "Date", "Cpubusy",
"UsedPercentMemory"), class = "data.frame", row.names = c(NA,
-10L))
任何想法我在这里缺少什么?
【问题讨论】:
-
我认为你试图尝试的是
print(xtable(d), type = "markdown")。当您使用format参数时,部分匹配会将其分配给format.args参数。如果您改用了type参数,则会在错误中告知您xtable仅支持HTML 和LaTeX 输出。 Pierre 建议使用knitr::kable是一个不错的选择。