标记一个数组列表

Question

我有一个文本文件，其值如下：

[2014-08-19 00:00:21,702] REC|SRC:923142676343|DST:9900|CNT:1|OPR:zong|\nADD BBCLANDAN\n 
[2014-08-19 00:01:02,958] REC|SRC:923138824807|DST:9900|CNT:1|OPR:zong|ADD TRIXXS 
[2014-08-19 00:01:12,799] REC|SRC:923125473547|DST:9900|CNT:1|OPR:zong|ADD SahafatMedia 
[2014-08-19 00:01:32,894] REC|SRC:923142676343|DST:9900|CNT:1|OPR:zong|ADD BBCMEDIA\n\n 
[2014-08-19 00:02:42,754] REC|SRC:923119511824|DST:9900|CNT:1|OPR:zong|ADD sMs
[2014-08-19 00:01:43,753] REC|SRC:923119511824|DST:9900|CNT:1|OPR:zong|ADD RIDAsMs

我已经阅读了文本文件并将其存储到带有输出的数组列表中：

输出：

923119511824|DST:9900|CNT:1|OPR:zong|ADD RIDAsMs
923119511824|DST:9900|CNT:1|OPR:zong|ADD sMs
923125473547|DST:9900|CNT:1|OPR:zong|ADD SahafatMedia 
923138824807|DST:9900|CNT:1|OPR:zong|ADD TRIXXS 
923142676343|DST:9900|CNT:1|OPR:zong|ADD BBCMEDIA\n\n 
923142676343|DST:9900|CNT:1|OPR:zong|\nADD BBCLANDAN\n 
[2014-08-19 00:01:02,958] REC|
[2014-08-19 00:01:12,799] REC|
[2014-08-19 00:01:32,894] REC|
[2014-08-19 00:01:43,753] REC|
[2014-08-19 00:02:42,754] REC|
[2014-08-19 00:00:21,702] REC|

现在我想标记这个数组列表以仅显示输出中的重复联系人号码，例如 923142676343 及其在 ADD 之后的内容，例如 TRIXXS 我需要帮助吗？？？

import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
import java.util.ArrayList;
import java.util.Collections;

public class pring
{

    public static final String FILE_LOCATION = "C:/Users/DfroJaCk DB/Desktop/zongrecv.txt";

    public static void main ( String [ ] args )
    {
        //Your reader
        BufferedReader in = null;
        //Where you store the Strings
        ArrayList < String > al = new ArrayList < String > ();
        try
        {
            //Open the file and give it to the reader
            in = new BufferedReader ( new FileReader ( FILE_LOCATION ) );
            String line;
            //As long as the file has more lines read a line at a time
            while ( ( line = in.readLine () ) != null )
            {
                //Split the line and stoe it in an array
                String [ ] splitLine = line.split ( "SRC:" );
                for ( int i = 0; i < splitLine.length; i++ )
                {
                    //Add each element of the split array into an ArrayList
                    al.add ( splitLine [ i ] );
                }
            }
        //Catch your possible problems
        } catch ( FileNotFoundException fnfe )
        {
            fnfe.printStackTrace ();
        } catch ( IOException ioe )
        {
            ioe.printStackTrace ();
        }       
        //Sort your list
        Collections.sort ( al );
        for ( String s : al )
        {
            //spit it out
            System.out.println ( s );
        } 
    }
}

Answer 1

你可以使用 java StringTokenizer。由于您的 arraylist 已经排序，您只需要检查连续的位置。使用 |作为分隔符，获取每个包含数字的条目的第一个标记，并将其与以下条目的第一个标记进行比较。如果它们相等，则获取最后一个标记中空间的索引并打印它之后的内容。

小心考虑超过 2 个条目包含相同电话号码的情况，不要打印两次。

但您可能会重新考虑您的方法，将字符串存储在 ArrayList 中的方式看起来很混乱。

    List<String> myList = new ArrayList();
    myList.add("923119511824|DST:9900|CNT:1|OPR:zong|ADD RIDAsMs");
    myList.add("923119511824|DST:9900|CNT:1|OPR:zong|ADD sMs");
    myList.add("923125473547|DST:9900|CNT:1|OPR:zong|ADD SahafatMedia");

    Collections.sort(myList);

    System.out.println(myList.toString());

    for (int i = 0; i < myList.size() - 1; i++) {

        String currentEntry = myList.get(i);
        String nextEntry = myList.get(i + 1);

        StringTokenizer tokenizer = new StringTokenizer(currentEntry, "|");
        String currentNumber = tokenizer.nextToken();

        tokenizer = new StringTokenizer(nextEntry, "|");
        String nextNumber = tokenizer.nextToken();

        String lastToken = "";

        if (currentNumber.equals(nextNumber)) {

            System.out.println(currentNumber + " duplicate");

            while (tokenizer.hasMoreTokens()) {

                lastToken = tokenizer.nextToken();
            }

            System.out.println("last token: " + lastToken);
            int index = lastToken.indexOf(" ");
            System.out.println("What you probably want: " + lastToken.substring(index + 1));

        }

    }

这样的输出将是：

[923119511824|DST:9900|CNT:1|OPR:zong|ADD RIDAsMs, 923119511824|DST:9900|CNT:1|OPR:zong|ADD sMs, 923125473547|DST:9900|CNT:1|OPR:zong|ADD SahafatMedia]
923119511824 duplicate
last token: ADD sMs
What you probably want: sMs