获得 3 个下一个工作日期，跳过周末和节假日

Question

我正在尝试使用 php 获取接下来的 3 天，但如果日期是周末或已定义的假期，我想跳过该日期。

例如，如果日期是 2013 年 12 月 23 日星期一 我的假期日期是array('2013-12-24', '2013-12-25'); 脚本将返回

Monday, December 23, 2013
Thursday, December 26, 2013
Friday, December 27, 2013
Monday, December 30, 2013

她是我当前的代码：

$arr_date = explode('-', '2013-12-23');
$counter = 0;
for ($iLoop = 0; $iLoop < 4; $iLoop++)
{
    $dayOfTheWeek = date("N", mktime(0, 0, 0, $arr_date[1], $arr_date[2]+$counter, $arr_date[0]));
    if ($dayOfTheWeek == 6) { $counter += 2; }
    $date = date("Y-m-d", mktime(0, 0, 0, $arr_date[1], $arr_date[2]+$counter, $arr_date[0]));
    echo $date;
    $counter++;
}

我遇到的问题是我什至不确定如何排除假期日期。

Answer 1

使用DateTime 在接下来的几天内递归，并使用in_array 进行字符串比较检查以查看下一个生成的日期是否属于假日或周末数组

$holidays = array('12-24', '12-25');
$weekend = array('Sun','Sat');
$date = new DateTime('2013-12-23');
$nextDay = clone $date;
$i = 0; // We have 0 future dates to start with
$nextDates = array(); // Empty array to hold the next 3 dates
while ($i < 3)
{
    $nextDay->add(new DateInterval('P1D')); // Add 1 day
    if (in_array($nextDay->format('m-d'), $holidays)) continue; // Don't include year to ensure the check is year independent
    // Note that you may need to do more complicated things for special holidays that don't use specific dates like "the last Friday of this month"
    if (in_array($nextDay->format('D'), $weekend)) continue;
    // These next lines will only execute if continue isn't called for this iteration
    $nextDates[] = $nextDay->format('Y-m-d');
    $i++;
}

将isset() 的建议用于O(1) 而不是O(n)：

$holidays = array('12-24' => '', '12-25' => '');
$weekend = array('Sun' => '','Sat' => '');
$date = new DateTime('2013-12-23');
$dayInterval = new DateInterval('P1D');
$nextDay = clone $date;
$i = 0;
$nextDates = array();
while ($i < 3)
{
    $nextDay->add($dayInterval);
    if (isset($holidays[$nextDay->format('m-d')])) continue;
    if (isset($weekend[$nextDay->format('D')])) continue;
    $nextDates[] = $nextDay->format('Y-m-d');
    $i++;
}

Answer 2

Here is a simple example 获取两个日期之间的工作日数；您可以简单地修改它以满足您的需求：

function number_of_working_dates($from, $days) {
    $workingDays = [1, 2, 3, 4, 5]; # date format = N (1 = Monday, ...)
    $holidayDays = ['*-12-25', '*-01-01', '2013-12-24', '2013-12-25']; # variable and fixed holidays

    $from = new DateTime($from);
    $dates = [];
    $dates[] = $from->format('Y-m-d');
    while ($days) {
        $from->modify('+1 day');

        if (!in_array($from->format('N'), $workingDays)) continue;
        if (in_array($from->format('Y-m-d'), $holidayDays)) continue;
        if (in_array($from->format('*-m-d'), $holidayDays)) continue;

        $dates[] = $from->format('Y-m-d');
        $days--;
    }
    return $dates;
}

print_r( number_of_working_dates('2013-12-23', 3) );

demo