如何在 JavaScript 中的日期范围之间获取重复的周日期计数？

Question

我有一组日期范围，我需要从中了解全年每周有多少人工作。

Eg: mainArray = ['01-01-2020','31-12-2020']; //year range

dateRanges = [
  [01-01-2020, 03-01-2020], //week 1
  [03-01-2020, 06-01-2020], //week 1 and 2
  [09-01-2020, 09-01-2020], //week 2
  [10-01-2020, 11-01-2020], //week 2
  [22-01-2020, 23-01-2020], //week 4
  ....
];

//first we need to find all the weeks from the mainArray date-range 

//then calculate the weeks colliding in the dateRanges array.

the output should be =>

workLoadInWeeks = [2,3,0,1,0,0,0,0,......,0];

说明： 由于 03-01-2020（第 1 周的日期）在第一个和第二个数组索引中重复，这就是为什么输出的第一个值是 2。

由于第 2 周的日期在 dateRanges[1]、dateRanges[2]、dateRanges[3] 中重复，这就是输出将 3 作为第二个值的原因。

因为没有人在第 3 周工作，所以它在输出数组中为 0

每周开始 - 周日， 每周 7 天，
我希望周日期范围从 1 月 1 日开始，因此第一周将是部分周，因为第一个开始是星期三。

这听起来可能令人困惑。我已经尽力解释了。

Answer 1

我们需要a function which results overall count of week:

function getISOWeeks(y) {
    var d,
        isLeap;

    d = new Date(y, 0, 1);
    isLeap = new Date(y, 1, 29).getMonth() === 1;

    //check for a Jan 1 that's a Thursday or a leap year that has a
    //Wednesday jan 1. Otherwise it's 52
    return d.getDay() === 4 || isLeap && d.getDay() === 3 ? 53 : 52
}

还有一个获取周数的函数：

function getWeek(date_string) {
    let [d, M, y] = date_string.split(/[- :]/);
    let passedDate = new Date(y, parseInt(M) - 1, d);
    let onejan = new Date(passedDate.getFullYear(), 0, 1);
    week = Math.ceil( (((passedDate - onejan) / 86400000) + onejan.getDay() + 1) / 7 );
    return week;
} 

这周结束后，我们每周计算人数。然后我们可以算出全年每周有多少人工作。

let weeks = dateRanges.map(s => s.map(d => this.getWeek(d)));

let distinctWeeks = weeks.map(s => 
    s.filter((item, pos) => s.indexOf(item) == pos)).flatMap(s => s);

let personPerWeek = distinctWeeks.reduce((a, c)=> {
    a[c] = a[c] || 0;
    a[c] += 1;
    return a;
},{})

const weekCount = getISOWeeks(2020);
let personsPerWeeks = [];

getWorkWeeks = (workWeeks, weekCount) => {
    for (let index = 1; index <= weekCount; index++) {
        let personCount = personPerWeek[index] || 0;
        workWeeks.push(personCount);
    }
    return workWeeks;
}

可以在这里看到一个例子：

function getWeek(date_string) {
    let [d, M, y] = date_string.split(/[- :]/);
    let passedDate = new Date(y, parseInt(M) - 1, d);
    let onejan = new Date(passedDate.getFullYear(), 0, 1);
    week = Math.ceil( (((passedDate - onejan) / 86400000) + onejan.getDay() + 1) / 7 );
    return week;
}

function getISOWeeks(y) {
    var d,
        isLeap;

    d = new Date(y, 0, 1);
    isLeap = new Date(y, 1, 29).getMonth() === 1;
    //check for a Jan 1 that's a Thursday or a leap year that has a
    //Wednesday jan 1. Otherwise it's 52
    return d.getDay() === 4 || isLeap && d.getDay() === 3 ? 53 : 52
}

let dateRanges = [
  ['01-01-2020', '03-01-2020'], //week 1
  ['03-01-2020', '06-01-2020'], //week 1 and 2
  ['09-01-2020', '09-01-2020'], //week 2
  ['10-01-2020', '11-01-2020'], //week 2
  ['22-01-2020', '23-01-2020'], //week 4
];

let weeks = dateRanges.map(s => s.map(d => this.getWeek(d)));
let distinctWeeks = weeks.map(s => s.filter((item, pos) => s.indexOf(item) == pos)).flatMap(s => s);
let personPerWeek = distinctWeeks.reduce((a, c)=> {
    a[c] = a[c] || 0;
    a[c] += 1;
    return a;
},{})

const weekCount = getISOWeeks(2020);
let personsPerWeeks = [];

getWorkWeeks = (workWeeks, weekCount) => {
    for (let index = 1; index <= weekCount; index++) {
        let personCount = personPerWeek[index] || 0;
        workWeeks.push(personCount);
    }
    return workWeeks;
}

getWorkWeeks(personsPerWeeks, weekCount);
console.log(personsPerWeeks)

Answer 2

检查这是否适合您。

dateRanges = [
 ["01-01-2020", "03-01-2020"], //week 1
  ["03-01-2020", "06-01-2020"], //week 1 and 2
  ["09-01-2020", "09-01-2020"], //week 2
  ["10-01-2020", "11-01-2020"], //week 2
  ["22-01-2020", "23-01-2020"], //week 4

];

mainArray = ['01-01-2020','31-12-2020'];
//console.log(dateRanges);
function diff_weeks(dt2, dt1) 
 {

  var diff =(dt2.getTime() - dt1.getTime()) / 1000;
  diff /= (60 * 60 * 24 * 7);
  return Math.abs(Math.round(diff));
  
 }

//for(var i = 0; i< dateRanges.length;i++){
//console.log(dateRanges[i][0]);
  var dateString1 = mainArray[0];
  var dateParts1 = dateString1.split("-"); 
  var dt1 = new Date(+dateParts1[2], dateParts1[1] - 1, +dateParts1[0]); 
  var dateString2 = mainArray[1];
  var dateParts2 = dateString2.split("-"); 
  var dt2 = new Date(+dateParts2[2], dateParts2[1] - 1, +dateParts2[0]); 
  //console.log(dt1);
  console.log(diff_weeks(dt1, dt2) + " Weeks");
//}