【发布时间】:2017-10-11 16:21:05
【问题描述】:
我正在为我的应用后端使用 php 和 slim 构建一个 restful api,而且我们有一个 web 版本,但我的团队使用纯 php 和 web 套装,我们分开工作。这只是我第一次承担后端责任 我对如何以安全和专业的方式处理身份验证有一个误解 我已经阅读了这个article 但我需要一个详细的方法来实现它在 php & slim 并将其扩展到 web 团队,以便使用相同的身份验证技术。
这是我使用的登录/注册代码: 帮我改进它:
$app->post('/api/create_user', function( $request , $response , $args ){
require('../config.php');
$email = $_POST['email'];
$qry= "select * from user where email ='". $email."'";
$result=$mysqli->query($qry);
if(mysqli_num_rows($result)>0){
$user = new stdClass();
$user->status=0;
$user->error=" the email is registered ";
$result = new stdClass();
$result->result=$user;
}
else {
$password = md5($_POST['password']);
$image=$_FILES['image']['name'];
$email=$_POST['email'] ;
$nickname =$_POST['nickname'];
$birthDay=$_POST['birthdate'];
$insert_req="INSERT INTO user VALUES ('', '$email', '$password','$nickname')";
$insert_user_result=$mysqli->query($insert_req);
if ($insert_user_result) {
$user = new stdClass();
$user->status=1;
$result = new stdClass();
$result->result=$user;}
else {$user = new stdClass();
$user->status=2;
$user->error=mysql_error();
$result = new stdClass();
$result->result=$user;}
}
if (isset($result)){
header('Content-type: application/json');
echo json_encode($result);}
});
?>
<?php
$app->post('/api/login', function( $request , $response , $args ){
require('../config.php');
$email =$_POST['email'];
$password = md5($_POST['password']);
$findemail_qry= "select user_id from user where email ='". $email."'";
$findemail_result =$mysqli->query($findemail_qry);
if(mysqli_num_rows($findemail_result)>0)
{
$login_qry="select user_id from user where email ='". $email."'AND password ='".$password."'";
$login_result =$mysqli->query($login_qry);
if(mysqli_num_rows($login_result)>0)
{
$data =mysqli_fetch_assoc ($login_result);
$user_id=$data['user_id'];
$user = new stdClass();
$user->status=1;
$user->user_id=$user_id;
$result = new stdClass();
$result->result=$user;}
else
{$user = new stdClass();
$user->status=2;
$user->error="wrong password";
$result = new stdClass();
$result->result=$user; }
}
else
{$user = new stdClass();
$user->status=0;
$user->error=" this email not registered ";
$result = new stdClass();
$result->result=$user;}
if (isset($result)){
header('Content-type: application/json');
echo json_encode($result);
}
});
?>
【问题讨论】:
-
您可能想查看 API 框架以获取灵感。 github.com/tuupola/slim-api-skeleton
标签: php security slim restful-authentication