drf-spectacular 找不到检查员课程答案

【问题标题】：drf-spectacular Can't find inspector classdrf-spectacular 找不到检查员课程
【发布时间】：2020-12-07 19:03:37
【问题描述】：

我正在尝试设置 drf-spectacular 来为我的 djangorestframework API 生成 AutoSchema。

我已经按照自述文件中的说明进行了设置，例如，在已安装的应用程序中，版本 = "~=0.11.1"，其余框架设置如下：

REST_FRAMEWORK = {
...,
    'DEFAULT_SCHEMA_CLASS': ('drf_spectacular.openapi.AutoSchema',),
}

我的 djangorestframework 是 3.12 版。运行以下命令时出现错误： ./manage.py spectacular --file schema.yml

这是我的一个示例视图：

class LinkListView(ListView):

    permission_classes = [AllowAny]
    template_name = "core/linklist.html"
    context_object_name = "link_list"

    def get_queryset(self):
        return Org.objects.all()

在阅读了一堆关于模式的内容后，我在想我有一些其他的库与此冲突，或者之前的一些其他招摇的替代方案是冲突的。根据错误，这是否有意义？有什么我想尝试的吗？

谢谢！

Traceback (most recent call last):
  File "./manage.py", line 23, in <module>
    main()
  File "./manage.py", line 19, in main
    execute_from_command_line(sys.argv)
  File "/usr/local/lib/python3.8/site-packages/django/core/management/__init__.py", line 401, in execute_from_command_line
    utility.execute()
  File "/usr/local/lib/python3.8/site-packages/django/core/management/__init__.py", line 395, in execute
    self.fetch_command(subcommand).run_from_argv(self.argv)
  File "/usr/local/lib/python3.8/site-packages/django/core/management/base.py", line 330, in run_from_argv
    self.execute(*args, **cmd_options)
  File "/usr/local/lib/python3.8/site-packages/django/core/management/base.py", line 371, in execute
    output = self.handle(*args, **options)
  File "/usr/local/lib/python3.8/site-packages/drf_spectacular/management/commands/spectacular.py", line 50, in handle
    schema = generator.get_schema(request=None, public=True)
  File "/usr/local/lib/python3.8/site-packages/drf_spectacular/generators.py", line 188, in get_schema
    paths=self.parse(request, public),
  File "/usr/local/lib/python3.8/site-packages/drf_spectacular/generators.py", line 130, in parse
    self._initialise_endpoints()
  File "/usr/local/lib/python3.8/site-packages/drf_spectacular/generators.py", line 113, in _initialise_endpoints
    self.endpoints = self.inspector.get_api_endpoints()
  File "/usr/local/lib/python3.8/site-packages/drf_spectacular/generators.py", line 22, in get_api_endpoints
    api_endpoints = self._get_api_endpoints(patterns, prefix)
  File "/usr/local/lib/python3.8/site-packages/drf_spectacular/generators.py", line 55, in _get_api_endpoints
    nested_endpoints = self._get_api_endpoints(
  File "/usr/local/lib/python3.8/site-packages/drf_spectacular/generators.py", line 49, in _get_api_endpoints
    if self.should_include_endpoint(path, callback):
  File "/usr/local/lib/python3.8/site-packages/rest_framework/schemas/generators.py", line 120, in should_include_endpoint
    if callback.cls.schema is None:
  File "/usr/local/lib/python3.8/site-packages/rest_framework/schemas/inspectors.py", line 120, in __get__
    assert issubclass(inspector_class, ViewInspector), (
TypeError: issubclass() arg 1 must be a class

我的图书馆：

[packages]
django = "~=3.1"
psycopg2 = "*"
djangorestframework = "~=3.12"
django-extensions = "*"
python-dotenv = "~=0.9"
django-cors-headers = "*"
django-filter = "*"
freezegun = "*"
pip = "*"
pytz = "*"
packaging = "*"
python-jose = "~=3.0"
cryptography = "~=2.0.3"
requests = "*"
twine = "*"
pyjwt = "*"
gunicorn = "*"
whitenoise = "*"
dj-database-url = "*"
boto = "*"
drf-spectacular = "~=0.11.1"

【问题讨论】：

标签： django

【解决方案1】：

这很可能只是一个小的设置问题。您将DEFAULT_SCHEMA_CLASS 定义为一个字符串的元组，而不是只是一个字符串。 Django 可能将此解决为一个列表/元组，其中一个类作为项目。那么错误消息是有道理的，因为元组不是类。我希望这能解决你的问题。应该是这样的：

REST_FRAMEWORK = {
    # YOUR SETTINGS
    'DEFAULT_SCHEMA_CLASS': 'drf_spectacular.openapi.AutoSchema',
}

【讨论】：