Graphql Schema 类型错误指示重复类型，它没有？

Question

我现在完全浪费了我的晚上试图解决这个问题，但即使经过多次搜索，我也无法找到答案。

我有我的服务器，它抓取我的“.graphql”文件文件夹并将它们合并成一个大文件夹，我将其与解析器一起传递到“makeExecutableSchema()”中，如下所示

        const folders      = fs.readdirSync(path.join(__dirname, './api'));
        const allResolvers = [];
        let typeDefs       = '';

        folders.forEach(folder => {
          if (folder !== 'directive') {
            typeDefs = typeDefs.concat(requireText(`./api/${folder}/${folder}.graphql`, require));
            const { resolver } = require(`./api/${folder}/${folder}.resolvers`);
            allResolvers.push(resolver);
          }
        });

        const resolvers = _.merge(allResolvers);
        return makeExecutableSchema({typeDefs, resolvers});

现在我经常收到错误

    Error: Schema must contain unique named types but contains multiple types named "Address".
        at invariant (C:\100hotwater\src\server\node_modules\graphql\jsutils\invariant.js:19:11)
        at typeMapReducer (C:\100hotwater\src\server\node_modules\graphql\type\schema.js:216:58)
        at Array.reduce (<anonymous>)
        at C:\100hotwater\src\server\node_modules\graphql\type\schema.js:237:36
        at Array.forEach (<anonymous>)
        at typeMapReducer (C:\100hotwater\src\server\node_modules\graphql\type\schema.js:232:51)
        at Array.reduce (<anonymous>)
        at new GraphQLSchema (C:\100hotwater\src\server\node_modules\graphql\type\schema.js:122:28)
        at Object.extendSchema (C:\100hotwater\src\server\node_modules\graphql\utilities\extendSchema.js:161:10)
        at buildSchemaFromTypeDefinitions (C:\100hotwater\src\server\node_modules\graphql-tools\dist\schemaGenerator.js:186:28)
        at _generateSchema (C:\100hotwater\src\server\node_modules\graphql-tools\dist\schemaGenerator.js:97:18)
        at Object.makeExecutableSchema (C:\100hotwater\src\server\node_modules\graphql-tools\dist\schemaGenerator.js:110:20)
        at Object.exports.allSchema (C:\100hotwater\src\server\helpers.js:22:28)
        at Server.graphQl (C:\100hotwater\src\server\index.js:28:34)
        at new Server (C:\100hotwater\src\server\index.js:17:14)
        at Object.<anonymous> (C:\100hotwater\src\server\index.js:42:19)

这个模式绝对不包含重复项，尽管如下所示，它在进入“makeExecutableSchema”()”函数之前打印出来。

      type Lead {
        _id: String
        owner: User
        address: Address
        steps: [Step]
      }

      type Mutation {
        createLead(
          owner: String!
          address: Address
          steps: [Step]
        ): Lead
      }

      type Address {
        lat: Int
        lng: Int
        formattedAddress: String
      }

      type Step {
        goto: String
        key: String
        str: String
      }

      type User {
        _id: String
        email: String
        firstName: String
        lastName: String
        mobile: Int
        phone: Int
        billingAddress: String
        password: String
        leads: [Lead]
      }

      type Query {
        signedInUser: User
        userByEmail(email: String!): User # @isAuthenticated
      }

      extend type Mutation {
        signIn(email: String!, password: String!): SignInResponse!
        createUser(
          email: String!
          firstName: String!
          lastName: String
          mobile: Int
          billingAddress: String
          password: String
        ): User
      }

      type SignInResponse {
        token: String
        refreshToken: String
      }

我在文件“node_modules\graphql\type\schema.js:216:58”中注意到它似乎循环输入两次，显然在检查中两次捕获地址并发布错误，但我仍然不确定从这往哪儿走。 Graphql 中这样的简单错误让人很难爱上它。

感谢任何帮助。

修复

简而言之，感谢下面的 Dan，我正在定义地址类型并将其用于我的输入（突变）和输出（查询 - 线索）。我当时没有意识到您需要以不同的方式定义类型和输入。下面的工作 .graphql 架构。

      type Lead {
        _id: String
        owner: User
        address: Address
        steps: [Step]
      }

      type Address {
        lat: Int
        lng: Int
        formattedAddress: String
      }

      type Mutation {
        createLead(
          owner: String!
          address: AddressInput 
          steps: [Step]
        ): Lead
      }

      input AddressInput {
        lat: Int
        lng: Int
        formattedAddress: String
      }

Answer 1

我不确定您的解析器模块是什么样的，但我怀疑您打算这样做：

const resolvers = _.merge(...allResolvers) // note the spread operator

否则，调用merge 实际上并没有做任何事情，您的resolvers 属性最终会成为一个数组而不是一个对象。

编辑：第一眼没注意到，但您使用类型作为输入。如果要使用与Address 类型具有相同形状的对象，则必须为其定义单独的输入类型：

type Address {
  lat: Int
  lng: Int
  formattedAddress: String
}

input AddressInput {
  lat: Int
  lng: Int
  formattedAddress: String
}

类型不能用于输入，输入也不能用于类型。如果我们以编程方式定义模式，我们通常会看到一个错误。显然，从 SDL 生成架构不会产生相同的错误。如果您为 Address 和 Step 添加适当的输入类型，您的架构应该会正确生成。