【发布时间】:2020-05-26 05:43:13
【问题描述】:
我是 R 新手,我不太清楚要使用什么结构以及它们的正确语法。
我有列表(更像是带有列和列名的表)。我想对多个列表执行相同的功能。我认为使用 for 循环是合理的。
我的功能是
1) 使用列计算新列。 (根据 log2foldchange 计算倍数变化)
2) 使用旧列表的子集创建一个新列表,并将其命名为调整原始列表名称的名称
以下是分别适用于这些表的代码行。
#take values from the log2FoldChange column and calculate Fold Change
resCondition_anno$FoldChange <- 2^resCondition_anno$log2FoldChange
#subset my dataset based on the values for each row in the padj column
resCondition_anno_padj05 <- subset(resCondition_anno, resCondition$padj <= 0.05)
我想对多个表执行这些功能。
当我尝试在 for 循环中执行此操作时
resfiles1 <- c(resCondition_anno,resVirus_anno,resInter_anno)
for (i in resfiles1){
i$FoldChange <- 2^i$log2FoldChange # I was trying to calculate a new column based on log2FoldChange column
i_with_padj05 <- paste(i,"_padj05") # I was trying to create a new name like resCondition_anno_padj05
i_with_padj05 <- subset(i, i[[padj]] <= 0.05) # I was trying to subset my dataset based on values in the padj column
}
我尝试使用 $ 访问我的表的列,结果给了我
Error: $ operator is invalid for atomic vectors
我尝试使用 [padj] 访问我的表的列,我明白了
Error in subset.default(i, i[padj] <= 0.05) : object 'padj' not found
当我尝试使用 `[[padj]] 访问表的列时,出现以下错误
Error in subset.default(i, i[[padj]] <= 0.05) : object 'padj' not found
我是不是完全走错了路? for 循环是实现我的目标的合理方法吗?我知道应用函数存在,但是当我尝试将多个文件输入其中时,我很难从中获取输出文件,所以我想尝试一下 for 循环。
我希望有一个代码适用于随机表并执行这些操作,然后我可以弄清楚我的表是否很奇怪。
dput(head(resCondition_anno))
structure(list(ensembl = c("ENSMUSG00000051951", "ENSMUSG00000102331",
"ENSMUSG00000025902", "ENSMUSG00000104238", "ENSMUSG00000102269",
"ENSMUSG00000096126"), baseMean = c(2.34691358937965, 0.169507902147731,
49.4591642836684, 0.253911076708937, 3.27439052075304, 0.258178295608587
), log2FoldChange = c(1.04699290132002, 1.89907052894015, 0.629095304499277,
0.0597400040882164, -0.291997327218544, 1.97984690635658), lfcSE = c(1.09309963258445,
4.36961772602319, 0.291712394209747, 4.37647193807779, 1.21524080418346,
4.3263845102792), stat = c(0.95782019324678, 0.434607933236415,
2.15656008104662, 0.0136502655411644, -0.240279396654017, 0.457621577937096
), pvalue = c(0.338153434807336, 0.66384703564954, 0.0310399577136823,
0.989109002094381, 0.810113666298446, 0.647224338296786), padj = c(NA,
NA, 0.106540309680362, NA, 0.911344697137259, NA), mgi_symbol = c("Xkr4",
"Gm19938", "Sox17", "Gm37587", "Gm7357", "Gm22307"), gene_biotype = c("protein_coding",
"sense_intronic", "protein_coding", "processed_transcript", "processed_pseudogene",
"snRNA")), class = c("data.table", "data.frame"), row.names = c(NA,
-6L), .internal.selfref = <pointer: 0x0000027bef7e1ef0>)`
目标 1 的预期结果
> dput(head(resCondition_anno))
structure(list(ensembl = c("ENSMUSG00000051951", "ENSMUSG00000102331",
"ENSMUSG00000025902", "ENSMUSG00000104238", "ENSMUSG00000102269",
"ENSMUSG00000096126"), baseMean = c(2.34691358937965, 0.169507902147731,
49.4591642836684, 0.253911076708937, 3.27439052075304, 0.258178295608587
), log2FoldChange = c(1.04699290132002, 1.89907052894015, 0.629095304499277,
0.0597400040882164, -0.291997327218544, 1.97984690635658), lfcSE = c(1.09309963258445,
4.36961772602319, 0.291712394209747, 4.37647193807779, 1.21524080418346,
4.3263845102792), stat = c(0.95782019324678, 0.434607933236415,
2.15656008104662, 0.0136502655411644, -0.240279396654017, 0.457621577937096
), pvalue = c(0.338153434807336, 0.66384703564954, 0.0310399577136823,
0.989109002094381, 0.810113666298446, 0.647224338296786), padj = c(NA,
NA, 0.106540309680362, NA, 0.911344697137259, NA), mgi_symbol = c("Xkr4",
"Gm19938", "Sox17", "Gm37587", "Gm7357", "Gm22307"), gene_biotype = c("protein_coding",
"sense_intronic", "protein_coding", "processed_transcript", "processed_pseudogene",
"snRNA"), FoldChange = c(2.0662186086592, 3.72972827627808, 1.54659483966075,
1.0422779093498, 0.816770504282921, 3.94451221821964)), class = c("data.table",
"data.frame"), row.names = c(NA, -6L), .internal.selfref = <pointer: 0x0000027bef7e1ef0>)
aim2 的预期结果
> dput(head(resCondition_anno_padj05))
structure(list(ensembl = c("ENSMUSG00000103922", "ENSMUSG00000025907",
"ENSMUSG00000061024", "ENSMUSG00000025911", "ENSMUSG00000025935",
"ENSMUSG00000025937"), baseMean = c(7.45083924607695, 1035.42915800337,
756.089939474399, 1510.50670239711, 2014.55644970672, 5206.99654662079
), log2FoldChange = c(3.31157886392159, -0.345358245876914, 0.340037961752993,
-0.637902858828505, 0.592795289538968, 0.59912370697665), lfcSE = c(0.984296895396084,
0.131191642000487, 0.0967702378760271, 0.120687031774959, 0.114283891072725,
0.161639505766009), stat = c(3.36441055479404, -2.63247140298489,
3.51386923517349, -5.28559572181691, 5.18704153292907, 3.70654255676794
), pvalue = c(0.000767073434065771, 0.00847661586751943, 0.000441630160084079,
1.25296333033368e-07, 2.13661093734535e-07, 0.000210107944374613
), padj = c(0.00522376704325313, 0.0385092726153939, 0.00325683272694307,
2.17721401368104e-06, 3.51690667040699e-06, 0.00168321660710376
), mgi_symbol = c("Gm6123", "Rb1cc1", "Rrs1", "Adhfe1", "Tram1",
"Lactb2"), gene_biotype = c("processed_pseudogene", "protein_coding",
"protein_coding", "protein_coding", "protein_coding", "protein_coding"
), FoldChange = c(9.92852128160573, 0.787112498791522, 1.26578990036559,
0.642646438673565, 1.5081660610658, 1.51479619975327)), class = c("data.table",
"data.frame"), row.names = c(NA, -6L), .internal.selfref = <pointer: 0x0000027bef7e1ef0>)
【问题讨论】:
-
请使用
dput添加数据并显示相同的预期输出。请阅读有关how to ask a good question 的信息以及如何提供reproducible example。 -
这个问题确实不清楚。对于您的问题“我想对多个列表执行相同的功能。”考虑
lapply。要访问列表的元素,请使用[[ ]]。 -
我做了 head() 而不是 dput() 并且希望这已经足够了,因为数据集很大。我尝试将它们作为代码输入,但我认为我需要练习如何做得更好。
-
我对 lapply 不满意,我不知道我是在要求它做一些不是设计要做的事情,还是我只是不知道该怎么做。当我输入多个表时,我很难单独返回每个输出表。我想出来的唯一方法是逐行指定每个文件的输出。我想尝试一下 for 循环,但如果 for 循环不是为了达到我的目的,我会更多地了解 lapply。我尝试了 [[ ]] 并发布了错误。
-
padj中的subset(i, i[[padj]] <= 0.05)是什么。据我所知i可以是resCondition_anno,resVirus_anno,resInter_anno之一。通过执行i[[padj]],您假设i是一个列表,对吗?padj是索引吗?
标签: r list for-loop filenames calculated-columns