bash脚本上的奇怪错误

Question

警告：我最近才开始学习 bash，并尝试做一个递归函数来计算一个术语......所以......

x0 = 0 x1 = 1 xm = 3 * xm-1 - 2 * xm-2

目前我写的函数是：

#!/bin/bash
calculate()
{
 if [ $1 -eq 0 ]
 then
 echo "0"
 fi
 if [ $1 -eq 1 ]
 then
 echo "1"
 fi
 if [ $1 -ge 1 ]
 then
 let var1 = `calculate [ $1-1 ]`;
 let var2 = `calculate [ $1-2 ]`;
 let var3 = 3*var1-2*var2;
 echo var3
fi
}
calculate 3

但是我遇到了一些奇怪的错误...不确定我是否正确执行...谁能告诉我导致这些问题的原因并更正我的代码以使其正常工作？非常感谢。

错误：

TP1p1.sh: line 4: [: [: integer expression expected
TP1p1.sh: line 8: [: [: integer expression expected
TP1p1.sh: line 12: [: [: integer expression expected
TP1p1.sh: line 14: let: =: syntax error: operand expected (error token is "=")
TP1p1.sh: line 4: [: [: integer expression expected
TP1p1.sh: line 8: [: [: integer expression expected
TP1p1.sh: line 12: [: [: integer expression expected
TP1p1.sh: line 15: let: =: syntax error: operand expected (error token is "=")
TP1p1.sh: line 16: let: =: syntax error: operand expected (error token is "=")

Answer 1

不确定你的计算，但你的语法清理的基本脚本是这个：

#!/bin/bash
calculate() {
 if [ $1 -eq 0 ]; then
    echo -n "0"
 elif [ $1 -eq 1 ]; then
    echo -n "1"
 elif [ $1 -ge 1 ]; then
    var1=$( calculate $(($1-1)) )
    var2=$( calculate $(($1-2)) )
    var3=$((3*(var1-2)*var2))
    echo $var3
fi
}
calculate 5