如何在 MySQL 中根据日期进行累积计数？答案

【问题标题】：How to make accumulative count based on date in MySQL?如何在 MySQL 中根据日期进行累积计数？
【发布时间】：2016-05-06 09:16:13
【问题描述】：

我有下表“testfinal”，并希望使其看起来像表“testfinal1”，并根据订单日期累积总和。

最终测试

+------+------------+-------+--------+----------+
| ID   | Orderdate  | apple | banana | quantity |
+------+------------+-------+--------+----------+
| 1005 | 2015-05-05 |     2 |      0 |        2 |
| 1005 | 2015-05-05 |     0 |      2 |        2 |
| 1005 | 2015-05-06 |     0 |      1 |        1 |
| 1006 | 2011-05-06 |     0 |      3 |        3 |
| 1006 | 2011-10-06 |     1 |      0 |        1 |
+------+------------+-------+--------+----------+

testfinal1

+------+------------+-------+--------+----------+
| ID   | Orderdate  | apple | banana | quantity |
+------+------------+-------+--------+----------+
| 1005 | 2015-05-05 |     2 |      2 |        4 |
| 1005 | 2015-05-06 |     2 |      3 |        5 |
| 1006 | 2011-05-06 |     0 |      3 |        3 |
| 1006 | 2011-10-06 |     1 |      3 |        4 |
+------+------------+-------+--------+----------+

现在我的代码如下但它不起作用

insert into testfinal1 (ID, Orderdate, apple, banana, quantity) 
select ID, Orderdate, 
(select sum(apple)from testfinal where date_format(OrderDate, '%Y-%m-%d') <= date_format(OrderDate, '%Y-%m-%d' ))  as apple, 
(select sum(banana)from testfinal where date_format(OrderDate, '%Y-%m-%d') <= date_format(OrderDate, '%Y-%m-%d' ))  as banana, 
(select sum(quantity)from testfinal where date_format(OrderDate, '%Y-%m-%d') <= date_format(OrderDate, '%Y-%m-%d' ))  as quantity 
from testfinal group by ID, Orderdate;

我认为问题是没有指定术语 orderdate。

【问题讨论】：

为什么需要条件？只做SELECT ID, Orderdate, SUM(apple), SUM(banana), SUM(quantity) FROM testfinal GROUP BY ID, Orderdate有什么问题？
testfina1 表中的最后一行是否正确？ 1006 | 2011-10-06 | 1 | 3 | 4 。不应该是1006 | 2011-10-06 | 1 | 0 | 4 这个吗？
您能解释一下您的预期输出吗？
感谢您的评论。最后一行是1的原因| 3 | 4 是因为它是testfinal 表中(0 + 1)、(3+0)、(3+1) 的结果。
在原始testfinal table上它是orderdate订购的货物数量。我想让新表“testfinal1”根据“orderdate”总结ID购买的商品，也就是说，ID在20110506买过(0,3)，分别买过(1,0)在 20111006。在 testfinal2 表中，我想显示用户 ID 1006 从过去到 20111006 总共购买了 (1,3)。

标签： mysql date accumulate

【解决方案1】：

这是您可能需要首先生成的查询：

SELECT
ID,
Orderdate,
SUM(apple) AS 'apple',
SUM(banana) AS 'banana',
SUM(quantity) AS 'quantity'
FROM testfinal
GROUP BY Orderdate;

DROP TABLE IF EXISTS testfinal1;

CREATE TABLE testfinal1 LIKE testfinal;

INSERT INTO testfinal1(ID,Orderdate,apple,banana,quantity)

SELECT
ID,
Orderdate,
SUM(apple) AS 'apple',
SUM(banana) AS 'banana',
SUM(quantity) AS 'quantity'
FROM testfinal
GROUP BY Orderdate;

【讨论】：