我们如何根据节点js中的另一个对象数组值对对象数组进行排序答案

【问题标题】：How can we sort the object array based on another object array value in node js我们如何根据节点js中的另一个对象数组值对对象数组进行排序
【发布时间】：2018-09-05 20:12:52
【问题描述】：

我们如何根据另一个对象数组值对对象数组进行排序，就像我们有一个对象数组一样：

var _userEnd = [{"userID":554,"tEnd":6},{"userID":597,"tEnd":3},{"userID":605,"tEnd":3},{"userID":617,"tEnd":1},{"userID":553,"tEnd":1},{"userID":616,"tEnd":1},{"userID":596,"tEnd":0}]

在此索引 1,2,3,4,5 具有相同的键“tEnd”值，即 3 和 1，所以我只需要根据另一个对象数组对这些索引进行排序

var _profsort=[{"userID":596,"score":100},{"userID":616,"score":95},{"userID":553,"score":100},{"userID":617,"score":85},{"userID":605,"score":95},{"userID":597,"score":85},{"userID":554,"score":100}]

这里用户 ID 597,605,617,553,616 的得分值为 85,95,85,100,95

所以根据分数，我想对我的第一个数组进行排序输出应该是：

[{"userID":554,"tEnd":6},{"userID":605,"tEnd":3},{"userID":597,"tEnd":3},{"userID":553,"tEnd":1},{"userID":616,"tEnd":1},{"userID":617,"tEnd":1},{"userID":596,"tEnd":0}]

【问题讨论】：

看看在developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…上使用 compareFunction 的例子

标签： javascript arrays node.js sorting object

【解决方案1】：

您可以获取tEnd 的增量并找到score 并获取该增量。

function getScore(uID) {
    return (_profsort.find(({ userID }) => userID === uID) || { score: 0 }).score;
}

var _userEnd = [{ userID: 554, tEnd: 6 }, { userID: 597, tEnd: 3 }, { userID: 605, tEnd: 3 }, { userID: 617, tEnd: 1 }, { userID: 553, tEnd: 1 }, { userID: 616, tEnd: 1 }, { userID: 596, tEnd: 0 }],
    _profsort = [{ userID: 596, score: 100 }, { userID: 616, score: 95 }, { userID: 553, score: 100 }, { userID: 617, score: 85 }, { userID: 605, score: 95 }, { userID: 597, score: 85 }, { userID: 554, score: 100 }];
    
_userEnd.sort(function (a, b) {
    return b.tEnd - a.tEnd || getScore(b.userID) - getScore(a.userID);
});

console.log(_userEnd);

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【讨论】：

一如既往的优雅 :) +1

【解决方案2】：

使用sort 和find

var fnGetScore = uid => _profsort.find(s => s.userID == uid).score; //method to get the score value based on userId

var output = _userEnd.sort( (a, b) => 
        (b.tEnd - a.tEnd) || 
           fnGetScore(b.userID) - fnGetScore(b.userID)) //compare tEnd first and if they are same, compare the score value

演示

var _userEnd = [{
  "userID": 554,
  "tEnd": 6
}, {
  "userID": 597,
  "tEnd": 3
}, {
  "userID": 605,
  "tEnd": 3
}, {
  "userID": 617,
  "tEnd": 1
}, {
  "userID": 553,
  "tEnd": 1
}, {
  "userID": 616,
  "tEnd": 1
}, {
  "userID": 596,
  "tEnd": 0
}];

var _profsort = [{
  "userID": 596,
  "score": 100
}, {
  "userID": 616,
  "score": 95
}, {
  "userID": 553,
  "score": 100
}, {
  "userID": 617,
  "score": 85
}, {
  "userID": 605,
  "score": 95
}, {
  "userID": 597,
  "score": 85
}, {
  "userID": 554,
  "score": 100
}];

var fnGetScore = uid => _profsort.find(s => s.userID == uid).score;

var output = _userEnd.sort((a, b) => (b.tEnd - a.tEnd) || fnGetScore(b.userID) - fnGetScore(b.userID))

console.log(output);

【讨论】：

【解决方案3】：

通过userID 使用Array.reduce 创建score 的对象。按tEnd 排序，如果相等，则按score 排序，您从sortObject 得到userId：

var _userEnd = [{"userID":554,"tEnd":6},{"userID":597,"tEnd":3},{"userID":605,"tEnd":3},{"userID":617,"tEnd":1},{"userID":553,"tEnd":1},{"userID":616,"tEnd":1},{"userID":596,"tEnd":0}]

var _profsort=[{"userID":596,"score":100},{"userID":616,"score":95},{"userID":553,"score":100},{"userID":617,"score":85},{"userID":605,"score":95},{"userID":597,"score":85},{"userID":554,"score":100}]

var sortObj = _profsort.reduce((r, o) => {
  r[o.userID] = o.score;

  return r;
}, Object.create(null));

_userEnd.sort((a, b) => b.tEnd - a.tEnd || sortObj[b.userID] - sortObj[a.userID]);

console.log(_userEnd);

【讨论】：