逻辑错误！使用字符串在指定位置插入数组

Question

我正在编写一个函数来提取单词中包含的单词的索引， 例如：4of Fo1r pe6ople g3ood th5e the2 这应该按顺序排列， 下面是代码，

function order(words){
    var result = []
    var sorting = words.split(' ').sort() 
    console.log(sorting);
    for(let i=0; i<sorting.length;i++)
    {
      var temp = sorting[i].split('').sort()//By this the words in the sentence get sorted and i will get the index(number) of the corresponding word at first position.
      console.log(temp);
      var valueHolder = parseInt(temp) //I will take the above obtained value and convert it into integer
        console.log(valueHolder);
      result.splice((valueHolder-1),0,sorting[i]) //will pass the index here
    }
    console.log(result);
  }

但我得到了错误的输出：[ 'Fo1r', 'the2', '4of', 'g3ood', 'pe6ople', 'th5e' ] 我错过了什么吗，谁能帮我这个谢谢。 上面的array.splice(index,0,item) 只会在指定位置插入元素，并带有0

预期输出为：[ 'Fo1r', 'the2', 'g3ood', '4of', 'th5e','pe6ople' ]

Answer 1

您可以使用正则表达式，然后您可以解析 9 以上的数字。

正则表达式const r = /\d+/; 查找一位或多位数字。然后在排序方法a.match(r)中使用正则表达式，然后对结果数字进行解析和比较。

const str = '4of Fo1r pe6ople g3ood th5e no71w the2';

function order(words) {
  let result = [];
  let sorting = words.split(' ');
  const r = /\d+/;
  
  sorting.sort((a,b) => {
    return parseInt(a.match(r)) - parseInt(b.match(r));
  });
  console.log(sorting.join(' '));
}
order(str);

Answer 2

问题是您的结果数组初始大小未设置，因此在循环期间拼接将无法正常工作。

简单修复：

words='4of Fo1r pe6ople g3ood th5e the2';

function order(words){
    var result = []
    var sorting = words.split(' '); 
    var result = new Array(sorting.length);
    console.log(result)
    for(let i=0; i<sorting.length;i++)
    {
      var temp = sorting[i].split('').sort()//By this the words in the sentence get sorted and i will get the index(number) of the corresponding word at first position.
      //console.log(temp);
      var valueHolder = parseInt(temp) //I will take the above obtained value and convert it into integer
        //console.log(valueHolder);
    result.splice(valueHolder-1,1,sorting[i]) //will pass the index here
   
    }
    console.log(result);
  }
  
order(words)

words='4of Fo1r pe6ople g3ood th5e the2';

function order(words){
    var result = []
    var sorting = words.split(' '); 
    var result = new Array(sorting.length);
   // console.log(result)
    for(let i=0; i<sorting.length;i++)
    {
      var temp = sorting[i].split('').sort()//By this the words in the sentence get sorted and i will get the index(number) of the corresponding word at first position.
      //console.log(temp);
      var valueHolder = parseInt(temp) //I will take the above obtained value and convert it into integer
        //console.log(valueHolder);
    result.splice(valueHolder-1,1,sorting[i]) //will pass the index here
   
    }
    console.log(result);
  }
  
order(words)

Answer 3

Array#splice 不是你应该在这里使用的正确的东西，而是使用索引将元素添加到所需的位置。

function order(words) {
  var result = [];
  var sorting = words.split(" ").sort();
  for (let i = 0; i < sorting.length; i++) {
    var temp = sorting[i].split("").sort();
    var valueHolder = parseInt(temp);
    result[valueHolder - 1] = sorting[i];
  }
  console.log(result);
}

order("4of Fo1r pe6ople g3ood th5e the2");

Answer 4

这适用于所有场景。使用regex的更少和最简单的代码。

解决方案

 function order(string) {
   var regex = /\d+/g;
   var matches = string.match(regex);        
   matches.sort(function(a, b){return parseInt(a)-parseInt(b)});

   var splittedArr = string.split(' ');

   var result = [];
   matches.forEach(item => {
      const findItem = splittedArr.find(a => a.includes(item));
      result.push(findItem);
   })
   console.log(result)
}

order('4of Fo1r pe6ople g3ood th5e the2') // your string
order('77of Fo1r pe6ople g3ood th8e the2') // other string
order('0of Fo1r pe6ople g4ood th8e the2') // other string