从数组中的文件中捕获值

Question

我有以下代码从文件中读取数字，然后为 10 位数范围内的数字的多次出现打印星号。问题在于我的 for 循环将数字添加到数组中。每当我执行代码时，它都会打印文件中的最后一个数字 (22) 20 次，并在 21-30 字符串中列出一个星号。我相信这一定是一个简单的订单问题。我错过了什么？

import java.util.Scanner;
import java.io.*;


public class histogram {

public static void main(String[] args) {

    try {

        final File numbers = new File("numbers.txt");
        Scanner filescan = new Scanner(numbers);

        int[] list = new int[101];


        while (filescan.hasNext()) {
            int num = filescan.nextInt();
            for(int i = 0; i < 101; i++)
            list[i] = num;

        }

        for(int value : list)
            System.out.println(value);

        String[] Stars = {"1-10 |", "11-20 |", "21-30 |", "31-40 |", "41-50 |", "51-60 |", "61-70 |", "71-80 |", "81-90 |", "91-100 |"};

        int number = 0;
        for (int st = 0; st < 101; st++)
            number = list[st];
        if (number < 11)
            Stars[0] += "*";
        else if (number < 21)
            Stars[1] += "*";
        else if (number < 31)
            Stars[2] += "*";
        else if (number < 41)
            Stars[3] += "*";
        else if (number < 51)
            Stars[4] += "*";
        else if (number < 61)
            Stars[5] += "*";
        else if (number < 71)
            Stars[6] += "*";
        else if (number < 81)
            Stars[7] += "*";
        else if (number < 91)
            Stars[8] += "*";
        else if (number < 101)
            Stars[9] += "*";

        for (int print = 0; print < 10; print++)
            System.out.println(Stars[print]);


        filescan.close();
    } catch (FileNotFoundException ex) {

    }

}

}

Answer 1

我认为这是-

while (filescan.hasNext()) {
    int num = filescan.nextInt();
    for(int i = 0; i < 101; i++)
    list[i] = num;
}

应该是这个-

int i = 0, num;
while (filescan.hasNext()) {
    num = filescan.nextInt();
    list[i] = num;
    if(i == 100)
        break;
    i++;
}