无法在 OSX 上成功执行 ipython notebook 命令

Question

我安装了 Anaconda python 发行版。但是，执行“ipython notebook”后，我无法成功执行，系统产生以下错误。我一头雾水，怎么了？

谢谢。

AbhayBhadani-MacBook:~ abhaybhadani$ ipython --version

3.0.0

AbhayBhadani-MacBook:~ abhaybhadani$ which ipython

/opt/anaconda/bin/ipython

AbhayBhadani-MacBook:~ abhaybhadani$ ipython notebook

[I 11:25:33.829 NotebookApp] Using existing profile dir: u'/Users/abhaybhadani/.ipython/profile_default'

[I 11:25:33.833 NotebookApp] Using MathJax from CDN: https://cdn.mathjax.org/mathjax/latest/MathJax.js
Traceback (most recent call last):

  File "/opt/anaconda/bin/ipython", line 11, in <module>
    sys.exit(start_ipython())

  File "/opt/anaconda/lib/python2.7/site-packages/IPython/__init__.py", line 120, in start_ipython
    return launch_new_instance(argv=argv, **kwargs)

  File "/opt/anaconda/lib/python2.7/site-packages/IPython/config/application.py", line 573, in launch_instance
    app.initialize(argv)

  File "<string>", line 2, in initialize

  File "/opt/anaconda/lib/python2.7/site-packages/IPython/config/application.py", line 75, in catch_config_error
    return method(app, *args, **kwargs)

  File "/opt/anaconda/lib/python2.7/site-packages/IPython/terminal/ipapp.py", line 321, in initialize
    super(TerminalIPythonApp, self).initialize(argv)

  File "<string>", line 2, in initialize

  File "/opt/anaconda/lib/python2.7/site-packages/IPython/config/application.py", line 75, in catch_config_error
    return method(app, *args, **kwargs)

  File "/opt/anaconda/lib/python2.7/site-packages/IPython/core/application.py", line 369, in initialize
    self.parse_command_line(argv)

  File "/opt/anaconda/lib/python2.7/site-packages/IPython/terminal/ipapp.py", line 316, in parse_command_line
    return super(TerminalIPythonApp, self).parse_command_line(argv)

  File "<string>", line 2, in parse_command_line

  File "/opt/anaconda/lib/python2.7/site-packages/IPython/config/application.py", line 75, in catch_config_error
    return method(app, *args, **kwargs)

  File "/opt/anaconda/lib/python2.7/site-packages/IPython/config/application.py", line 471, in parse_command_line
    return self.initialize_subcommand(subc, subargv)

  File "<string>", line 2, in initialize_subcommand

  File "/opt/anaconda/lib/python2.7/site-packages/IPython/config/application.py", line 75, in catch_config_error
    return method(app, *args, **kwargs)

  File "/opt/anaconda/lib/python2.7/site-packages/IPython/config/application.py", line 409, in initialize_subcommand
    self.subapp.initialize(argv)

  File "<string>", line 2, in initialize

  File "/opt/anaconda/lib/python2.7/site-packages/IPython/config/application.py", line 75, in catch_config_error
    return method(app, *args, **kwargs)

  File "/opt/anaconda/lib/python2.7/site-packages/IPython/html/notebookapp.py", line 980, in initialize
    self.init_webapp()

  File "/opt/anaconda/lib/python2.7/site-packages/IPython/html/notebookapp.py", line 842, in init_webapp
    self.http_server.listen(port, self.ip)

  File "/opt/anaconda/lib/python2.7/site-packages/tornado/tcpserver.py", line 125, in listen
    sockets = bind_sockets(port, address=address)

  File "/opt/anaconda/lib/python2.7/site-packages/tornado/netutil.py", line 145, in bind_sockets
    sock.bind(sockaddr)

  File "/opt/anaconda/lib/python2.7/socket.py", line 224, in meth
    return getattr(self._sock,name)(*args)

error: [Errno 49] Can't assign requested address


If you suspect this is an IPython bug, please report it at:
    https://github.com/ipython/ipython/issues
or send an email to the mailing list at ipython-dev@scipy.org


You can print a more detailed traceback right now with "%tb", or use "%debug"
to interactively debug it.


Extra-detailed tracebacks for bug-reporting purposes can be enabled via:
    c.Application.verbose_crash=True

Answer 1

这只是建立在@Abhay Bhadani 已经为自己提供的答案之上，因为我自己似乎无法找到根本原因

您可以尝试编辑您的 ipython 配置文件。就我而言，我必须使用以下命令创建配置文件：

ipython profile create

然后将以下行附加到 ipython 笔记本配置。在我的情况下，该文件位于~/.ipython/profile_default/ipython_notebook_config.py，这是创建时没有名称的配置文件的默认位置。找到后，附加以下配置选项：

c.NotebookApp.ip = '127.0.0.1'

然后，当运行ipython notebook 时，它将照常打开，无需提供 ip 参数。因此，您的解决方案并没有太大的改进，但我更喜欢这种方式:)

如果您真的想知道在配置或命令行中未提供 ip 时调用 的原因或地址是什么或调用什么地址，则可以在相同的情况下附加以下内容配置文件：

c.Application.verbose_crash=True

在我的例子中，运行 ipython notebook 会得到以下输出：

--> 228     return getattr(self._sock,name)(*args)
    global getattr = undefined
    self._sock = <socket object, fd=6, family=2, type=1, protocol=6>
    name = 'bind'
    args = (('192.168.77.104', 8888),)
229
230 for _m in _socketmethods:
231     p = partial(meth,_m)
232     p.__name__ = _m
233     p.__doc__ = getattr(_realsocket,_m).__doc__
234     m = MethodType(p,None,_socketobject)
235     setattr(_socketobject,_m,m)
236
237 socket = SocketType = _socketobject
238
239 class _fileobject(object):
240     """Faux file object attached to a socket object."""
241
242     default_bufsize = 8192
243     name = "<socket>"

error: [Errno 49] Can't assign requested address

这只是给了我一个提示，它可能正在尝试访问无效的 IP。