当从实时数据库中删除对象时，Firebase 函数（用 NodeJS 编写）从 Cloud Storage 中删除文件

Question

我是 NodeJS 的新手，我正在尝试为 Cloud Functions for Firebase 编写下一个方法。

我想要达到的目标：

1. 当用户从 Firebase DB 中移除照片对象时，该函数应该被触发；
2. 代码应从 Storage 中删除与 Photo obj 对应的文件对象。

这些是我的 Firebase 数据库结构：

照片/{userUID}/{photoUID}

{
"dateCreated":      "2017-07-27T16:40:31.000000Z",
"isProfilePhoto":   true,
"isSafe":           true,
"uid":              "{photoUID}",
"userUID":          "{userUID}"
}

以及 Firebase 存储格式：

照片/{userUID}/{photoUID}.png

以及我正在使用的 NodeJS 代码：

    const functions = require('firebase-functions')
    const googleCloudStorage = require('@google-cloud/storage')({keyFilename: 'firebase_admin_sdk.json' })
    const admin = require('firebase-admin')
    const vision = require('@google-cloud/vision')();

    admin.initializeApp(functions.config().firebase)

    exports.sanitizePhoto = functions.database.ref('photos/{userUID}/{photoUID}')
        .onDelete(event => {

            let photoUID = event.data.key
            let userUID = event.data.ref.parent.key

            console.log(`userUID: ${userUID}, photoUID: ${photoUID}`);

            if (typeof photoUID === 'undefined' || typeof userUID === 'undefined') {
                console.error('Error while sanitize photo, user uid or photo uid are missing');
                return
            }

            console.log(`Deleting photo: ${photoUID}`)

            googleCloudStorage.bucket(`photos/${userUID}/${photoUID}.png`).delete().then(() => {
                console.log(`Successfully deleted photo with UID: ${photoUID}, userUID : ${userUID}`)
            }).catch(err => {
                console.log(`Failed to remove photo, error: ${err}`)
            });

        });

当我运行它时，我得到下一个错误：“ApiError: Not found”

我认为这部分代码是导致问题的原因：

googleCloudStorage.bucket(`photos/${userUID}/${photoUID}.png`).delete()

提前感谢您的支持和耐心。

Answer 1

找到问题，这里是适合我的代码：

const functions = require('firebase-functions');

实时数据库：

exports.sanitizePhoto = functions.database.ref('photos/{userUID}/{photoUID}').onDelete(event => {

        let photoUID = event.data.key
        let userUID = event.data.ref.parent.key

        console.log(`userUID: ${userUID}, photoUID: ${photoUID}`);

        if (typeof photoUID === 'undefined' || typeof userUID === 'undefined') {
            console.error('Error while sanitize photo, user uid or photo uid are missing');
            return
        }

        console.log(`Deleting photo: ${photoUID}`)

        const filePath = `photos/${userUID}/${photoUID}.png`
        const bucket = googleCloudStorage.bucket('myBucket-12345.appspot.com')
        const file = bucket.file(filePath)

        file.delete().then(() => {
            console.log(`Successfully deleted photo with UID: ${photoUID}, userUID : ${userUID}`)
        }).catch(err => {
            console.log(`Failed to remove photo, error: ${err}`)
        });

    });

这里还有相同的代码，但用于 Firestore（不确定它是否有效，因为我不是 NodeJS 开发人员，也没有实际测试过）：

exports.sanitizePhoto = functions.firestore.document('users/{userUID}/photos/{photoUID}').onDelete((snap, context) =>{

    const deletedValue = snap.data();

    let photoUID = context.params.photoUID 
    let userUID = context.params.userUID

    console.log(`userUID: ${userUID}, photoUID: ${photoUID}`);

    if (typeof photoUID === 'undefined' || typeof userUID === 'undefined') {
        console.error('Error while sanitize photo, user uid or photo uid are missing');
        return
    }

    console.log(`Deleting photo: ${photoUID}`)

    const filePath = `photos/${userUID}/${photoUID}.png`
    const bucket = googleCloudStorage.bucket('myBucket-12345.appspot.com')
    const file = bucket.file(filePath)

    file.delete().then(() => {
        console.log(`Successfully deleted photo with UID: ${photoUID}, userUID : ${userUID}`)
    }).catch(err => {
        console.error(`Failed to remove photo, error: ${err}`)
    });

});

您还可以注意到我的路径从：

photos/{userUID}/{photoUID} 

到：

users/{userUID}/photos/{photoUID}

Answer 2

试试这个代码

const gcs  = require('@google-cloud/storage')()

    const fileBucketPush = 'Storage bucket.appspot.com'; // The Storage bucket that contains the file.
    const filePathPush = 'folder/'+nameImage; // File path in the bucket.
    vision.detectSafeSearch(gcs.bucket(fileBucketPush).file(filePathPush))
      .then((results) => {
       ..///

      })
      .catch((err) => {
        console.error('ERROR:', err);
      });

您启用 Cloud Vision API 吗？