Quickdb add 不是 Quick.db 的函数错误

Question

尝试按照 youtube 上的教程制作警告系统，我猜它已经过时了，因为我收到了这个错误

UnhandledPromiseRejectionWarning: TypeError: db.add is not a function

这是代码的工作原理。

const db = require('quickdb')
const member = message.member
        const user = message.mentions.members.first()
        const reason = args.slice(1).join(" ")
if (reason) {

            let embed = new Discord.MessageEmbed()
                .setTitle('Warning')
                .setColor('GREEN')
                .setDescription(`${user.user.username} Was Warned For ${reason} By ${member.user.username}`)
                .setFooter(`Bot by Yaay#6969`);

                user.send(`You have been warned in **${message.guild.name}** for ${reason} By ${member.user.username}`)

                db.add('userInfo.warningsnumber', 1)
                db.push('userInfo.warnings', `${reason}`)
                db.get('userInfo.warningsnumber')
                db.get('userInfo.warnings')

            message.channel.send(embed)
        }

Answer 1

尝试像这样要求它

 const db = require('quick.db');

我认为你这里有一个错字

const db = require('quickdb') //TYPO it's quick.db not quickdb