如何将 PHP 数组转换为特定的 JSON 输出数组

Question

这是我要转换的数组

Array
(
   [0] => stdClass Object
       (
           [Item1] => 10/12/2021
           [Item2] => Array
               (
                   [0] => 0
                   [1] => 0
                   [2] => 0
                   [3] => 0
               )

       )

   [1] => stdClass Object
       (
           [Item1] => 10/11/2021
           [Item2] => Array
               (
                   [0] => 0
                   [1] => 0
                   [2] => 0
                   [3] => 0
               )

       )

   [2] => stdClass Object
       (
           [Item1] => 10/10/2021
           [Item2] => Array
               (
                   [0] => 0
                   [1] => 0
                   [2] => 0
                   [3] => 0
               )

       )

   [3] => stdClass Object
       (
           [Item1] => 10/09/2021
           [Item2] => Array
               (
                   [0] => 0
                   [1] => 0
                   [2] => 0
                   [3] => 0
               )

       )

   [4] => stdClass Object
       (
           [Item1] => 10/08/2021
           [Item2] => Array
               (
                   [0] => 0
                   [1] => 0
                   [2] => 0
                   [3] => 0
               )

       )

   [5] => stdClass Object
       (
           [Item1] => 10/07/2021
           [Item2] => Array
               (
                   [0] => 0
                   [1] => 0
                   [2] => 0
                   [3] => 0
               )

       )

   [6] => stdClass Object
       (
           [Item1] => 10/06/2021
           [Item2] => Array
               (
                   [0] => 3729195
                   [1] => 0
                   [2] => 0
                   [3] => 0
               )

       )

   [7] => stdClass Object
       (
           [Item1] => 10/05/2021
           [Item2] => Array
               (
                   [0] => 7458390
                   [1] => 0
                   [2] => 0
                   [3] => 0
               )

       )

   [8] => stdClass Object
       (
           [Item1] => 10/04/2021
           [Item2] => Array
               (
                   [0] => 0
                   [1] => 0
                   [2] => 0
                   [3] => 0
               )

       )

   [9] => stdClass Object
       (
           [Item1] => 10/03/2021
           [Item2] => Array
               (
                   [0] => 0
                   [1] => 0
                   [2] => 0
                   [3] => 0
               )

       )

)

我想要这样的数组输出 -

[{name:"", data:[0,0,0,0,0,0,3729195,7458390,0,0]},
{name:"", data:[0,0,0,0,0,0,0,0,0,0]},
{name:"", data:[0,0,0,0,0,0,0,0,0,0]},
{name:"", data:[0,0,0,0,0,0,0,0,0,0]}]

问题是[Item2][0]输入数组的第一个元素是每4行数据的第一个元素：[0]，[Item2][1]的第二个元素是每个数据集的第二列所有 4 行的 data[1] 元素，我希望你明白我的意思。

日期应该像这样在另一个单独的列表中 -

['10/12/2021', '10/11/2021', '10/10/2021', '10/09/2021', '10/08/2021', '10/07/2021', '10/06/2021', '10/05/2021', '10/04/2021', '10/03/2021'],

我已经做了一些测试，这就是我目前所做的 -

$ChartDataNew  = stripcslashes(trim(json_encode($jobs->charts_last10days), "\""));

$replace1 = str_replace('Item1', name, $ChartDataNew);
$replace2 = str_replace('Item2', data, $replace1);
print_r($replace2);

上面的代码给了我一个 JSON 对象的输出

[{"name":"10/12/2021","data":[0,0,0,0]},{"name":"10/11/2021","data":[0,0,0,0]},{"name":"10/10/2021","data":[0,0,0,0]},{"name":"10/09/2021","data":[0,0,0,0]},{"name":"10/08/2021","data":[0,0,0,0]},{"name":"10/07/2021","data":[0,0,0,0]},{"name":"10/06/2021","data":[3729195,0,0,0]},{"name":"10/05/2021","data":[7458390,0,0,0]},{"name":"10/04/2021","data":[0,0,0,0]},{"name":"10/03/2021","data":[0,0,0,0]}]

这个 JSON 看起来不错，但它不正确。首先，我想让上面给出的 JSON 输出没有“”，并且名称应该是名称：“”。当您看到我的 json 对象输出中的数据与输入数组中的日期不匹配时。

要获得我已经完成的日期列表，并且很好 -

$chartDataSeries = array();
$chartDateLabels = array();
$chartSeriesList = array();
foreach($jobs->charts_last10days as $chartData){
array_push($chartDateLabels, "'".$chartData->Item1."'");
array_push($chartDataSeries, $chartData->Item2);         
           
} 

$chartDateLabels1 = implode(', ', ($chartDateLabels));
echo ($chartDateLabels1);

它为我提供了日期列表的正确输出，请参阅

['10/12/2021', '10/11/2021', '10/10/2021', '10/09/2021', '10/08/2021', '10/07/2021', '10/06/2021', '10/05/2021', '10/04/2021', '10/03/2021']

请让我知道我做错了什么或帮助我如何做到这一点，可能是编写一些函数或任何其他方式来做到这一点。

提前致谢

Answer 1

可能有一个更优雅的解决方案，但我能想到的最简单的方法是遍历每个元素，然后构造另一个数组：

$resultArr = [];

// Iterate over each element of the original array
foreach ($dataArr as $key => $arr) {
    // Set the date
    $datesArr[$key] = $arr->Item1;

    // Iterate over each element of Item2
    foreach ($arr->Item2 as $i => $v) {
        // Set 'data' on the resulting array item $i to the value
        //  using the $key from the outer loop as the index for the inner data array
        $resultArr[$i]['data'][$key] = $v;

        // Set the name
        $resultArr[$i]['name'] = '';
    }
}

// Convert from an array to JSON
echo json_encode($resultArr) . PHP_EOL;

// The dates are in $datesArr
echo json_encode($datesArr) . PHP_EOL;

$dataArr 是当前存储数据的变量。运行此循环后，$resultArr 将是一个数组，其中每个元素都是另一个数组，其中包含正确格式的数据，$datesArr 是它们自己数组中数据的日期。