【发布时间】:2019-08-06 10:57:16
【问题描述】:
我想将带有联系信息的数据框转换为包含类似信息的城市列表,例如电话号码出现在多列中。
我尝试过同时使用reshape2::dcast() 和tidyr::spread(),但都没有解决我的问题。我还检查了堆栈溢出的其他帖子,例如
尚未找到可行的解决方案。在我看来,这些问题应该相当简单(并且可以通过 spread 或 dcast 解决)。
tmp <- tibble(municipality = c("M1", "M2"),
name1 = c("n1", "n2"), name2 = c("n3", "n4"), name3 = c(NA, "n5"), # placeholder names
phone1 = c("p1", "p2"), phone2 = c("p3", "p4"), phone3 = c(NA, "p5")) # placeholder phone numbers
#solution 1
tmp %>% gather("colname", "value", -municipality) %>%
filter(municipality == "M1") %>% #too simplify, should be replaced with group_by(municipality)
na.omit() %>% mutate(colname = str_replace(colname, "\\d", replacement = "")) %>%
spread(., key = "colname", value = "value")
#Solution 2
tmp %>% gather("colname", "value", -municipality) %>%
filter(municipality == "M1") %>% # same as above
na.omit() %>% mutate(colname = str_replace(colname, "\\d", replacement = "")) %>%
dcast(municipality + value ~colname)
解决方案 1 导致以下错误: 错误:每行输出必须由唯一的键组合标识。
解决方案 2 产生以下数据框(这是所需的结果,但需要折叠):
municipality value name phone
1 M1 n1 n1 <NA>
2 M1 n3 n3 <NA>
3 M1 p1 <NA> p1
4 M1 p3 <NA> p3
【问题讨论】: