【发布时间】:2018-11-26 22:05:37
【问题描述】:
在过去的几个小时里,我一直在尝试解决一个问题,但没有成功。
我在另一篇类似的帖子中发现了一条错误消息:Plotting Ellipse3d in R Plotly with surface ellipse
唯一的回应强调这是因为缺乏样本。但我的样本量 = 3;这是创建椭圆的最小值。
另一个帖子的另一个回复强调,这可能是因为输入到 ellipse3d() 中的矩阵不是对称方阵,但实际上是因为我在输入时取了 cov(data_frame_of_interest)。
关于问题的更多信息:
我正在尝试使用 R 和 prcomp() 中的 rgl 包绘制 3d PCA;其中 top_noSR3 是一个 prcomp() 对象。我对以下示例的前 3 台 PC 感兴趣。
#Here is the exact PCA object obtained from prcomp(). It is
#top_noSR3$x[,c(1,2,3)].
top_noSR3 <- list(x = structure(c(-1.51867921165966, 4.7156146538954, -0.812795773332441,
-2.38413966890339, -2.57305046487183, 8.4906222835565, 1.66680581870767,
-7.5843776373923, 3.35199279752431, 2.4452307290032, -7.33666903970592,
1.53944551317846, -1.72127982564219, 2.68563509110228, -2.75720515666432,
1.79284989120424, -0.962414945057766, -1.44498205066367, -0.270435252418625,
2.67783224814005, -0.780985238414212, 7.3028581587737, -1.3641698814598,
-5.15770303889969, 0.989625278145346, 0.101301456051966, 1.96037141973899,
-3.05129815393625, -2.29377625653868, -4.3601221831666, 5.9554046825257,
0.698493757179566, 2.3724852157055, 0.0505080025883657, -1.97013906903266,
-0.452854149261224), .Dim = c(12L, 3L), .Dimnames = list(c("SR1.4",
"SR1.5", "SR1.6", "SR1.7", "SR2.2", "SR2.3", "SR2.4", "SR2.5",
"CI1.4", "CI1.5", "CI1.6", "CI1.7"), c("PC1", "PC2", "PC3"))))
#col_object is an array of colours used for colouring the points in the PCA:
col_object <- c("blue","red","green","purple","blue","red",
"green","purple","blue","red","green","purple")
plot3d(top_noSR3$x[,c(1,2,3)], type = "s", size = 1, col = col_object)
#Divide object into 3 components for 3d ellipse plotting function
for_plot3d <- function(casetime){
return(top_noSR3$x[casetime, c(1,2,3)])
}
BASE <- c("SR1.4", "SR2.2", "CI1.4")
EA <- c("SR1.5", "SR2.3", "CI1.5")
LA <- c("SR1.6", "SR2.4", "CI1.6")
FU <- c("SR1.7", "SR2.5", "CI1.7")
BASE_for3d <- for_plot3d(BASE)
EA_for3d <- for_plot3d(EA)
LA_for3d <- for_plot3d(LA)
FU_for3d <- for_plot3d(FU)
#The following arguments used above (BASE,EA, etc.) ^ are
#timepoints/rownames of interest. length(BASE) = ... = length(FU) = 3
center4plot <- function(x){
k <- mean(x[,1])
h <- mean(x[,2])
z <- mean(x[,3])
return(c(k,h,z))
}
center_base <- center4plot(BASE_for3d)
center_EA <- center4plot(EA_for3d)
center_LA <- center4plot(LA_for3d)
center_FU <- center4plot(FU_for3d)
ellipse_base <- ellipse3d(cov(BASE_for3d),level = 0.95, centre=center_base)
ellipse_EA <- ellipse3d(cov(EA_for3d), level = 0.95, centre=center_EA)
#ERROR appears here, in ellipse_LA
ellipse_LA <- ellipse3d(cov(LA_for3d), level = 0.95, centre=center_LA)
ellipse_FU <- ellipse3d(cov(FU_for3d), level = 0.95, centre=center_FU)
当我使用 ellipse_LA 运行该行时,我收到以下消息: ellipse3d() chol.default(cov) 中的错误:3 阶的前导次要不是正定的
感谢大家的时间和精力。
【问题讨论】:
-
非退化椭圆需要 3 个点,但 3-D 椭圆体需要 4 个点。我怀疑您根本不需要进行分解,但是由于您尚未发布可重现的示例,因此我不确定。
-
所有其他椭圆都只需要 3 个点...
-
你想看什么样的例子
-
只需发布足够的代码和数据,我们就可以通过运行您的代码来重现问题。我认为在这种情况下,这意味着我们需要查看
top_noSR3和col_object(使用dput(top_noSR3)和dput(col_object)),但可能还缺少其他内容。如果这些内容太大或太机密而无法发布,请发布仍能说明您的问题的较小的虚假值。 -
我刚刚添加了感兴趣的时间点,关于 top_noSR3,刚刚添加了 dput() 对象,我明白你现在在说什么了。