要获得正方形范围,您需要在地图投影坐标中指定它。这涉及到一些坐标变换。这是您需要的代码 sn-p。
# crs of your choice
crg = cimgt.StamenTerrain().crs # or cimgt.GoogleTiles().crs
# set map limits, in degrees
lonmin, lonmax = -22, -15
latmin, latmax = 63, 65
# do coordinate transformation
LL = crg.transform_point(lonmin, latmin, ccrs.Geodetic())
UR = crg.transform_point(lonmax, latmax, ccrs.Geodetic())
EW = UR[0] - LL[0]
SN = UR[1] - LL[1]
# get side of the square extent (in map units, usually meters)
side = max(EW, SN) # larger value is in effect
mid_x, mid_y = LL[0]+EW/2.0, LL[1]+SN/2.0 # center location
# the extent preserves the center location
extent = [mid_x-side/2.0, mid_x+side/2.0, mid_y-side/2.0, mid_y+side/2.0]
# this sets square extent
# crs=crg signifies that projection coordinates is used in extent
ax.set_extent(extent, crs=crg)
希望对你有帮助。
编辑
这是一个完整的工作代码及其生成的地图。
import matplotlib.pyplot as plt
import cartopy.crs as ccrs
from cartopy.mpl.gridliner import LONGITUDE_FORMATTER, LATITUDE_FORMATTER
import cartopy.io.img_tiles as cimgt
def make_map(projection=ccrs.PlateCarree()):
fig, ax = plt.subplots(figsize=(10, 10),
subplot_kw=dict(projection=projection))
gl = ax.gridlines(draw_labels=True)
gl.xlabels_top = gl.ylabels_right = False
gl.xformatter = LONGITUDE_FORMATTER
gl.yformatter = LATITUDE_FORMATTER
return fig, ax
request = cimgt.StamenTerrain() # very responsive
crg = request.crs #crs of the projection
fig, ax = make_map(projection = crg)
# specify map extent here
lonmin, lonmax = -22, -15
latmin, latmax = 63, 65
LL = crg.transform_point(lonmin, latmin, ccrs.Geodetic())
UR = crg.transform_point(lonmax, latmax, ccrs.Geodetic())
EW = UR[0] - LL[0]
SN = UR[1] - LL[1]
side = max(EW,SN)
mid_x, mid_y = LL[0]+EW/2.0, LL[1]+SN/2.0 #center location
extent = [mid_x-side/2.0, mid_x+side/2.0, mid_y-side/2.0, mid_y+side/2.0] # map coordinates, meters
ax.set_extent(extent, crs=crg)
ax.add_image(request, 8)
# add a marker at center of the map
plt.plot(mid_x, mid_y, marker='o', \
color='red', markersize=10, \
alpha=0.7, transform = crg)
plt.show()