【问题标题】:How to store specific links as a list and then click them如何将特定链接存储为列表然后单击它们
【发布时间】:2019-03-25 00:08:51
【问题描述】:

我一直在关注如何在网页上抓取网页 http://kanview.ks.gov/PayRates/PayRates_Agency.aspx 的教程。可以在这里找到教程:https://medium.freecodecamp.org/better-web-scraping-in-python-with-selenium-beautiful-soup-and-pandas-d6390592e251。它的布局类似于我要抓取信息的网站:https://www.giiresearch.com/topics/TL11.shtml。我唯一的问题是报告标题的 giiresearch 网站上的链接没有按照时间顺序排列,例如。以下来自gii研究

a href="/report/an806147-fixed-mobile-convergence-from-challenger-operators.html">Fixed-Mobile Convergence from Challenger Operators: Case Studies and Analysis</a>

a href="/annual/an378138-convergence-strategies.html">Convergence Strategies</a>

kanview网站上的链接是有顺序的,例如。

a id="MainContent_uxLevel2_JobTitles_uxJobTitleBtn_1" href="javascript:__doPostBack('ctl00$MainContent$uxLevel2_JobTitles$ctl03$uxJobTitleBtn','')">Academic Advisor</a

a id="MainContent_uxLevel2_JobTitles_uxJobTitleBtn_2" href="javascript:__doPostBack('ctl00$MainContent$uxLevel2_JobTitles$ctl04$uxJobTitleBtn','')">Academic Program Specialist</a>

这意味着我不能将他们代码行中使用的方法用于我的项目:

python_button = driver.find_element_by_id('MainContent_uxLevel2_JobTitles_uxJobTitleBtn_' + str(x))

我试图 find_elements_by_class_name 但所有链接都具有相同的“列表标题”类名,因此 for 循环仅打开第一个链接而不会继续。

我在想应该有一种方法可以将报告标题链接存储在列表中,以便我可以逐个打开它们以检索有关每个报告的更多信息并将其保存在 Excel 工作表中。

在这个项目中,我想编制一份竞争对手报告的 Excel 表格,其中包含有关其标题、价格、出版商、出版日期等的统计数据,以进行市场分析。

这是我的代码:

from selenium import webdriver
from webdriver_manager.chrome import ChromeDriverManager
from selenium.webdriver.common.keys import Keys
from bs4 import BeautifulSoup
import re
import pandas as pd
from tabulate import tabulate
import os

#launch url
url = "https://www.giiresearch.com/topics/TL11.shtml"

# create a new Chrome session
driver = webdriver.Chrome(ChromeDriverManager().install())
driver.implicitly_wait(30)
driver.get(url)

#Selenium hands the page source to Beautiful Soup
soup_level1=BeautifulSoup(driver.page_source, 'lxml')


datalist = [] #empty list
x = 0 #counter

#Beautiful Soup finds all Job Title links on the agency page and the loop begins
for link in soup_level1.find_all("div", {"class": "list_title"}):

    #Selenium visits each Job Title page
    python_button = driver.find_elements_by_class_name('list_title')
    python_button.click() #click link

    #Selenium hands of the source of the specific job page to Beautiful Soup
    soup_level2=BeautifulSoup(driver.page_source, 'lxml')

    #Beautiful Soup grabs the HTML table on the page
    table = soup_level2.find_all('table')[0]

    #Giving the HTML table to pandas to put in a dataframe object
    df = pd.read_html(str(table),header=0)

    #Store the dataframe in a list
    datalist.append(df[0])

    #Ask Selenium to click the back button
    driver.execute_script("window.history.go(-1)")

    #increment the counter variable before starting the loop over
    x += 1

    #end loop block

#loop has completed

#end the Selenium browser session
driver.quit()

#combine all pandas dataframes in the list into one big dataframe
result = pd.concat([pd.DataFrame(datalist[i]) for i in range(len(datalist))],ignore_index=True)

#convert the pandas dataframe to JSON
json_records = result.to_json(orient='records')

#pretty print to CLI with tabulate
#converts to an ascii table
print(tabulate(result, headers=["Report Title","Publisher","Published Date","Price"],tablefmt='psql'))

#get current working directory
path = os.getcwd()

#open, write, and close the file
f = open(path + "\\fhsu_payroll_data.json","w") #FHSU
f.write(json_records)
f.close()

【问题讨论】:

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标签: python html list matrix web-scraping


【解决方案1】:

您可以通过使用子a 标记元素与css 选择器中的父类的关系来存储报告标题链接。虽然您可以从访问过的页面中获取标题,但您也可以在列表理解中收集元组 [(link.get_attribute('href') , link.text) for link in ....... 然后解压成可以循环的独立元组。

代码:

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

url = 'https://www.giiresearch.com/topics/TL11.shtml'
driver = webdriver.Chrome()
driver.get(url)
titles, links = zip(*[(link.text, link.get_attribute('href')) for link in WebDriverWait(driver,10).until(EC.presence_of_all_elements_located((By.CSS_SELECTOR, ".list_title a")))]) #separate tuples
dates = [item.text for item in driver.find_elements_by_css_selector('.plist_dateinfo .plist_info_dd2')]
data = list(zip(dates, titles, links))

然后您可以循环 links 元组和 driver.get 每个单独的元组。

你有标题和日期信息,以防你想做其他事情。例如:

print(data[3])

给予

('January 30, 2019', 'Global Telco Converged Plans & Bundles Insights 2019: A Look at Bundling Strategies from Around the World', 'https://www.giiresearch.com/report/wise780587-global-telco-converged-plans-bundles-insights-look.html')

【讨论】:

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