JSON 对象未正确格式化为 Javascript

Question

我想在 JavaScript 中使用 JSON 对象作为键 -> 值数组，但我不明白为什么它没有以我想要的方式返回我的对象​​：

我尝试了以下方法：

var obj = JSON.stringify(result);

var result = Object.keys(obj).map(function (key) { 

    // Using Number() to convert key to number type 
    // Using obj[key] to retrieve key value 
    return [Number(key), obj[key]]; 
}); 

for(var i = 0; i < result.length; i++) { 
    for(var z = 0; z < result[i].length; z++) { 
        console.log(result[i][z]); 
    } 
    
} 

但我在 console.log 中得到以下行

writeback.js:159 0
writeback.js:159 "
writeback.js:159 1
writeback.js:159 {
writeback.js:159 2
writeback.js:159 \
writeback.js:159 3
writeback.js:159 "
writeback.js:159 4
writeback.js:159 r
writeback.js:159 5
writeback.js:159 o
writeback.js:159 6
writeback.js:159 w
writeback.js:159 7
writeback.js:159 n
writeback.js:159 8
writeback.js:159 u
writeback.js:159 9
writeback.js:159 m
writeback.js:159 10
writeback.js:159 b
writeback.js:159 11
writeback.js:159 e
writeback.js:159 12
writeback.js:159 r
writeback.js:159 13
writeback.js:159 \
writeback.js:159 14
writeback.js:159 "
writeback.js:159 15
writeback.js:159 :
writeback.js:159 16
writeback.js:159 1
writeback.js:159 17
writeback.js:159 ,
writeback.js:159 18
writeback.js:159 \
writeback.js:159 19
writeback.js:159 "
writeback.js:159 20
writeback.js:159 I
writeback.js:159 21
writeback.js:159 D
writeback.js:159 22
writeback.js:159 \
writeback.js:159 23
writeback.js:159 "
writeback.js:159 24
writeback.js:159 :
writeback.js:159 25
writeback.js:159 1
writeback.js:159 26
writeback.js:159 }
writeback.js:159 27
writeback.js:159 {
writeback.js:159 28
writeback.js:159 \
writeback.js:159 29
writeback.js:159 "
writeback.js:159 30
writeback.js:159 r
writeback.js:159 31
writeback.js:159 o
writeback.js:159 32
writeback.js:159 w
writeback.js:159 33
writeback.js:159 n
writeback.js:159 34
writeback.js:159 u
writeback.js:159 35
writeback.js:159 m
writeback.js:159 36
writeback.js:159 b
writeback.js:159 37
writeback.js:159 e
writeback.js:159 38
writeback.js:159 r
writeback.js:159 39
writeback.js:159 \
writeback.js:159 40
writeback.js:159 "
writeback.js:159 41
writeback.js:159 :
writeback.js:159 42
writeback.js:159 2
writeback.js:159 43
writeback.js:159 ,
writeback.js:159 44
writeback.js:159 \
writeback.js:159 45
writeback.js:159 "
writeback.js:159 46
writeback.js:159 I
writeback.js:159 47
writeback.js:159 D
writeback.js:159 48
writeback.js:159 \
writeback.js:159 49
writeback.js:159 "
writeback.js:159 50
writeback.js:159 :
writeback.js:159 51
writeback.js:159 2
writeback.js:159 52
writeback.js:159 }
writeback.js:159 53
writeback.js:159 "

似乎 JSON 对象中的每个字符都获得了一个键，但键和值在对象本身中。

UPDATE：变量result的值是

{"rownumber":1,"ID":1}{"rownumber":2,"ID":2}

有人可以帮我解决这个问题吗？

Answer 1

似乎您将Object 传递给JSON.stringify，它将对象转换为String（参见@Barmar 的第一条评论）。

换行

var obj = JSON.stringify(result);

进入

var obj = result;

=== 编辑 ===

OP更新问题后，上面的建议其实还不足以解决问题。

输入是String，内容如下：

'{"rownumber":1,"ID":1}{"rownumber":2,"ID":2}'

由于它不是有效的 JSON 字符串，因此仅使用 JSON.parse 是不够的。首先，需要将字符串拆分为 2 个单独的“对象描述”，然后将其中的每一个都传递给 JSON.parse。

var splitted = result.
  split('}{'). // <-- split in 2
  map((partialObjectStr, i) => {
    return JSON.parse( // <-- parse into object
      i < 1 
        ? `${partialObjectStr}}` // <-- add right } before parsing
        : `{${partialObjectStr}` // <-- add left { before parsing
    );
  });

var objA = splitted[0];
var objB = splitted[1];

console.log(objA);
console.log(objB);

Answer 2

如果你想在内存中改变或复制，你应该包装 JSON.parse()

var obj = JSON.parse(JSON.stringify(result));

否则只需删除 JSON.stringify()

var obj = result;