从两个熊猫 groupby 对象绘制堆积条形图？

Question

考虑两个输入文件b.dat 和c.dat：

string,date,number
a string,2/5/11 9:16am,1.0
a string,3/5/11 10:44pm,2.0
a string,4/22/11 12:07pm,3.0
a string,4/22/11 12:10pm,4.0
a string,4/29/11 11:59am,1.0
a string,5/2/11 1:41pm,2.0
a string,5/2/11 2:02pm,3.0
a string,5/2/11 2:56pm,4.0
a string,5/2/11 3:00pm,5.0
a string,5/2/14 3:02pm,6.0
a string,5/2/14 3:18pm,7.0


string,date,number
a string,2/5/10 9:16am,4.0
a string,3/4/10 10:44pm,5.0
a string,4/22/10 12:07pm,3.0
a string,6/22/10 12:10pm,6.0
a string,4/29/11 11:59am,1.0
a string,5/2/11 1:41pm,9.0
a string,5/27/11 2:02pm,3.0
a string,6/2/11 2:56pm,14.0
a string,5/2/11 3:00pm,5.0
a string,5/8/14 3:02pm,16.0
a string,5/2/14 3:18pm,7.0

我可以将这些导入并分组为每月总计：

b=pd.read_csv('b.dat')
c=pd.read_csv('c.dat')
b.index=b['date']
c.index=c['date']
b['date']=pd.to_datetime(b['date'],format='%m/%d/%y %I:%M%p')
c['date']=pd.to_datetime(c['date'],format='%m/%d/%y %I:%M%p')
bg=pd.groupby(b,by=[b.index.year,b.index.month])
cg=pd.groupby(c,by=[c.index.year,c.index.month])

接下来我想绘制一个堆积条形图。但是，我的尝试会产生单独的图表。

bg.sum().plot(kind='bar',stacked=True)
cg.sum().plot(kind='bar',stacked=True)

有谁知道如何做到这一点？

Answer 1

您可以使用 concat 创建一个新的数据框并绘制它，但我认为您必须重命名其中一列。

cgs = cg.sum()
cgs.columns = ['number2']
d = pd.concat([bg.sum(), cgs], axis=1)
d.plot(kind='bar', stacked=True)