使用 Pillow 分解长文本

Question

默认情况下，在编写文本时，Python 中的 Pillow 返回从侧面截断的文本。我想让它从最后一个单词中截断文本，即自动换行。

当前：

预期：

我发现this 很有用，但它会破坏最后一个字母而不是单词的文本。

Answer 1

这是我的代码，用于演示如何从长字符串中拆分单词，但仅使用左对齐，并且有/没有边缘对齐。您可以更改以下代码以使其具有中心对齐方式，以及沿边缘的填充数。

from PIL import Image, ImageDraw, ImageFont

def split(string):
    return string.split()

def draw_text(string, font="cour.ttf", size=16, width=320, height=240,
        background=(255, 255, 255, 0), color='black', edge=False,
        justification='center', mode="RGBA"):

    im = Image.new(mode=mode, size=(width, height), color=background)
    draw = ImageDraw.Draw(im, mode)
    font = ImageFont.truetype(font=font, size=size)

    words = split(string)
    length = len(words)
    lines, start = [], 0

    for i in range(length):
        line = ' '.join(words[start:i+1])
        w, h = font.getsize(line)
        if (w > width):
            lines.append(' '.join(words[start:i]))
            start = i
        elif i == length-1:
            lines.append(line)

    len_lines = len(lines)
    dy = (height-h)//(len_lines-1)
    for i, line in enumerate(lines):
        if edge and (i != len_lines-1):
            words = line.split()
            length = len(words)
            delta = (width - sum(map(lambda x:font.getsize(x)[0], words)))//(length-1) if length>1 else 0
            x = 0
            for j, word in enumerate(words):
                draw.text((x, i*dy), word, fill=color, font=font)
                x += font.getsize(word)[0]+delta
        else:
            draw.text((0, i*dy), line, fill=color, font=font)

    im.show()    # using im.save to save image to file

width, height = 960, 120
font, size = "arial.ttf", 32
align = True
string = (
    "Python is an easy to learn, powerful programming language. "
    "It has efficient high-level data structures and a simple "
    "but effective approach to object-oriented programming.").strip()

draw_text(string, font=font, size=size, width=width, height=height, edge=True)
draw_text(string, font=font, size=size, width=width, height=height, edge=False)