如果与其他列的文本匹配，则仅从前 2 行中删除文本行

Question

我有一个 Pandas 数据框 (Python 3.x)，如下所示：

title	type	content
Mango	Paragraph	Mango is called the king of fruits. It is a stone fruit produced from numerous species of tropical trees.....
Dates	Paragraph	[Dates] /n [Paragraph] /n Dates have been a staple food of the Middle East and the Indus Valley for thousands of years......
Mango	Essay	"Mango" "Essay" Mango is called the king of fruits. It is a stone fruit produced from numerous species of tropical trees.....
Apple	Article	Apple /n Article /n An apple is an edible fruit produced by an apple tree.....
......	......	...................................................................................

在某些行中，“title”和“type”列的文本也出现在“content”列中。如果“内容”列中存在“标题”和“类型”，我需要删除整行。 我尝试了很多次，但未能删除包含其他列相同文本的整行。 请帮忙！！

Answer 1

用numpy.char.find怎么样：

import numpy as np

values = df.values.astype(str)

mask = (np.char.find(values[:,[2,2]], values[:,[0,1]]) == -1).any(1) 
df[mask]    

输出

   title       type                                            content
0  Mango  Paragraph  Mango is called the king of fruits. It is a st...